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denis-greek [22]
3 years ago
12

Find the first four iterates of the function f(x) = 2x with an initial value of x0 = 2.

Mathematics
1 answer:
DiKsa [7]3 years ago
8 0

Answer:

d.  4, 8, 16, 32

Step-by-step explanation:

We'll use the formula  f(x) = 2x  for each iteration.  The output of the first iteration will be come the input of the second iteration, and so on.

So, we start with x0 = 2 and we plug that into the base equation:

x0 = 2 ==> f(x) = 2(2) = 4

x1 = 4 ==> f(x) = 2(4) = 8

x2 = 8 ==> f(x) = 2(2) = 16

x3 = 16 ==> f(x) = 2(2) = 32

x4 = 32 ==> f(x) = 2(2) = 64

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Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

Let's first establish that the shape is a triangle meaning that the following formula is applicable as displayed below:

Angle sum of a triangle = 180°

As well as this, the shape is an equilateral triangle meaning that each angle of the triangle is equivalent in value. Also, the following formula is also applicable as displayed below:

Each angle of an equilateral triangle = the same value

Therefore:

Each angle of an equilateral triangle = angle sum of a triangle ÷ no. of angles in a triangle = 180° ÷ 3 = 60°

Based on this, the following is applicable:

2x - 4 = 60°

2x = 60 + 4

2x = 64

x = 64 / 2

x = 32°

ANSWER:

Therefore, the answer is:

The value of ( x ) is 32°


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nikdorinn [45]

Answer:

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Step-by-step explanation:

There are a couple of ways you can get there:

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... ∠BAD = 55° +90° = 145°

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