Question

Find the first four iterates of the function f(x) = 2x with an initial value of x0 = 2.

Answer 1

Answer:

d.  4, 8, 16, 32

Step-by-step explanation:

We'll use the formula  f(x) = 2x  for each iteration.  The output of the first iteration will be come the input of the second iteration, and so on.

So, we start with x0 = 2 and we plug that into the base equation:

x0 = 2 ==> f(x) = 2(2) = 4

x1 = 4 ==> f(x) = 2(4) = 8

x2 = 8 ==> f(x) = 2(2) = 16

x3 = 16 ==> f(x) = 2(2) = 32

x4 = 32 ==> f(x) = 2(2) = 64