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boyakko [2]
3 years ago
5

Suppose y varies directly with x, and y=8 when x= -2. Find x when y=12

Mathematics
2 answers:
grigory [225]3 years ago
8 0

<em>X would be -3, -2 x 12 then divide it by 8. </em>

<em>Best of luck,</em>

<em>Echy</em>

N76 [4]3 years ago
6 0
X would be -3, -2*12 then divide 8
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The height and diameter of a cone-shaped storage tank are 9 feet (height) and 14 feet
lana [24]

Answer: 461.60 is the volume of liquid the tank can hold.

Step-by-step explanation:

We were given;

Height H = 9 ft

Diameter D = 14 ft

Pie π = 3.14

We will make use the formula of volume of a cone to get volume of water the tank can hold because it is said that the tank is in the shape of a cone

So

V = 1/3 * πr2h

First we need to find our radius r

Radius = 1/2 of diameter = 14/2 = 7

So using the formula

V = 1/3 * πr2h

V = 1/3 (3.14 * 7² * 9)

V = (3.14 * 49 * 9)/3

V = 1384.74 / 3

V = 461.58 = 461.60 (nearest ten)

3 0
3 years ago
Tom read 20 books, 12 magazines, and 18 newspaper articles last year.
neonofarm [45]

Answer: 24% of the books read are magazine

Step-by-step explanation:sum of the books read is 20+12+18=50 books.

Therefore 12 of the books are magazine.

Then, 12 of 50 =24%( 12÷50)× 100/1 = 24%

8 0
3 years ago
Read 2 more answers
Identify the axis of symmetry and vertex of f(x) = –2x2 –2x–1.
Leya [2.2K]

<span>Given the quadratic equation: f(x) = -2x^2 - 2x - 1, the axis of symmetry can be obtained by finding the line that divides the function into two congruent or identical halves. Thus, it should pass through the vertex and is equal to the x-coordinate of the vertex. </span>

<span>Note that a quadratic equation in standard form: y = ax^2 + bx + c, has the vertex located at (h,k) where, h = -b/2a and k is determined by evaluating y at h. In this case, a = -2, b = -2, thus, h = -0.5, k = 0.5. Thus, the vertex is located at (-0.5, 0.5) and the axis of symmetry is at x = -0.5. </span>

4 0
3 years ago
Read 2 more answers
the position of a submarine relative to the water surface was -32 1/4 feet . A downward navigational manuever increased it's dep
tester [92]

Answer:

Position of the submarine now relative to the water surface =-47\ \frac{3}{4}

Step-by-step explanation:

It says that the position of a submarine relative to the water surface was -32 1/4 feet . A downward navigational maneuver increased it's depth by 15 1/2 feet.

Now we need to find about what is the position of the submarine now relative to the water surface.

Downward navigation means we 15 1/2 is negative

so we will just add both values to get the final answer:

Position of the submarine now relative to the water surface = -32\ \frac{1}{4}-15\ \frac{1}{2}

=-32\ \frac{1}{4}-15\ \frac{2}{4}

=-47\ \frac{3}{4}


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3 years ago
How to solve for x and y
KonstantinChe [14]
7 is the answer for both
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