Given:
Circumference of a circle = C
Diameter of a circle = d
To find:
The relationship between the circumference, c, and diameter, d, of any circle.
Solution:
We know that, circumference of a circle is
It can be written as
![[\because d=2r]](https://tex.z-dn.net/?f=%5B%5Cbecause%20d%3D2r%5D)
On dividing both sides by d, we get
Therefore, the correct option is (F).
Answer:
{x,y} = {-2,-3}
Step-by-step explanation:
System of Linear Equations entered :
[1] -9x + 4y = 6
[2] 9x + 5y = -33
Graphic Representation of the Equations :
4y - 9x = 6 5y + 9x = -33
Solve by Substitution :
// Solve equation [2] for the variable y
[2] 5y = -9x - 33
[2] y = -9x/5 - 33/5
// Plug this in for variable y in equation [1]
[1] -9x + 4•(-9x/5-33/5) = 6
[1] -81x/5 = 162/5
[1] -81x = 162
// Solve equation [1] for the variable x
[1] 81x = - 162
[1] x = - 2
// By now we know this much :
x = -2
y = -9x/5-33/5
// Use the x value to solve for y
y = -(9/5)(-2)-33/5 = -3
The reciprocal of 6/5 is D. 5/6
Reciprocal simply means swapping the position of the numbers in the fraction. The numerator becomes the denominator and the denominator becomes the numerator.
We need to get reciprocal of a fraction when division is performed.
For example: 2 ÷ 1/5
2 may be a whole number but in fraction form it is 2/1.
1st fraction = 2/1
2nd fraction = 1/5
In dividing fractions, the 1st step we need to do is to get the reciprocal of the 2nd fraction.
1/5 ⇒ 5/1
Then, we multiply the 1st fraction to the reciprocal of the 2nd fraction.
2/1 * 5/1 = 10
So, 2 ÷ 1/5 = 10
