Question

Use technology to find the P-value. The claim is that for 12 AM body temperatures, the mean is μ, < 98.6°F. The sample size is n = 4 and the test statistic is t = -2.503.

Answer 1

Answer:

P-value = 0.043738

Step-by-step explanation:

We are given the following in the question:

The claim is that for 12 AM body temperatures, the mean is μ, < 98.6° F

Sample size, n = 4

Degree of freedom = n - 1 = 4 - 1 = 3

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} } = -2.503$

W have to calculate the p-value for the given hypothesis.

P-value:

• The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct.
• The p-value is used as an alternative to rejection points.
• We can calculate the p-value with the help of standard normal table.

P-value = 0.043738

The p value for given test is 0.043738.