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3 years ago

A rectangular painting's width is 6 less than twice its length.

Mathematics

1 answer:

atroni [7]3 years ago

7 0

Answer: Paintings length is 16, width is 26, area is 416 square inches.

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Find the missing side. Round to the nearest tenth

Ghella [55]

Answer:

x = 12.5

Step-by-step explanation:

From the diagram,

Applying

tanФ = Opposite/Adjacent...................... Equation 1

From the diagram,

Given: Opposite = 16, Adjacent = x, Ф = 52°

Substitute these values into equation 1

tan52° = 16/x

make x the subject of the equation

x = 16/tan52°

x = 16/1.27994

x = 12.5.

6 0

2 years ago

Find the length of the diagonal of a square with perimeter of 24

julsineya [31]

Answer:

d = 6sqrt(2) or 8.4853

Step-by-step explanation:

Formula

P = 4*s

s^2 + s^2 = d^2 where d is the diagonal and s is the side.

Givens

P = 24

Solution

P = 4s Substitute for s

24 = 4*s Divide by 4

24/4 = s

s = 6

================

d^2 = s^2 + s^2

d^2 = 6^2 + 6^2

d^2 = 36 + 26

d^2 = 72

d = sqrt(72)

Factors of 72

72: 6 * 6 * 2

Rule: Every pair of = factors allows you to take one of them outside the sqrt sign and throw the other a way. If there are no pairs, whatever you started with stays under the root sign.

sqrt(6*6*2) = 6sqrt(2)

The diagonal length is either
d = 6*sqrt(2) or
d = 8.4853

8 0

3 years ago

Which expression is equivalent to 6 OF 5y3 (5) Ο Ο 125y3 125y5

ValentinkaMS [17]

Answer:

✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️

6 0

2 years ago

Y = (x) = (1/9)^x Find f(x) when x = (1/2) Round your answer to the nearest thousandth.

irina [24]

Answer:

0.333

Step-by-step explanation:

6 0

2 years ago

A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len

Gnom [1K]

Answer:

$t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723$

E. -0.723

$df=n-1=93-1=92$

$p_v =2*P(t_{(92)}$

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

$\bar X=5.97$ represent the sample mean for the length

$s=0.4$ represent the sample standard deviation

$n=93$ sample size

$\mu_o =6$ represent the value that we want to test

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:

Null hypothesis: $\mu = 6$

Alternative hypothesis: $\mu \neq 6$

since we don't know the population deviation the statistic is:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing in formula (1) we got:

$t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723$

E. -0.723

P value

The degrees of freedom are given by:

$df=n-1=93-1=92$

Since is a two tailed test the p value would be:

$p_v =2*P(t_{(92)}$

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

5 0

2 years ago