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Lesechka [4]
3 years ago
6

Solve the inequality

Mathematics
1 answer:
GenaCL600 [577]3 years ago
8 0

Answer:

\large\boxed{x>-25}

Step-by-step explanation:

-\dfrac{3}{10}x-7

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The factored expression is: 3(5n-6)
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Read 2 more answers
Write a recursive rule and an explicit rule for the<br> sequence<br> 3,7,11,15
m_a_m_a [10]

Answer:

The Recursive formula for the sequence is:

aₙ = aₙ₋₁ + d

The Explicit formula for the sequence is:

a_n=4n-1

Step-by-step explanation:

Given the sequence

3,7,11,15

Here:

a₁ = 3

computing the differences of all the adjacent terms

7 - 3 = 4, 11 - 7 = 4, 15 - 11 = 4

The difference between all the adjacent terms is the same and equal to

d = 4

We know that a recursive formula basically defines each term of a sequence using the previous term(s).

The recursive formula of the Arithmetic sequence always involves the first term.

a₁ = 3

We know that, in the Arithmetic sequence, every next term can be obtained by adding the common difference and the preceding term.

so

The recursive formula of the sequence is:

aₙ = aₙ₋₁ + d

substitute n = 2 to find the 2nd term

a₂ = a₂₋₁ + d

a₂ = a₁+ d

substitute a₁ = 3 and d = 4

a₂ = 3 + 4

a₂ = 7

Thus, the recursive formula for the sequence 3,7,11,15 is:

aₙ = aₙ₋₁ + d

<u>An explicit rule for the sequence</u>

Given the sequence

3,7,11,15

We already know that

a₁ = 3

d = 4

An arithmetic sequence has a constant difference 'd' and is defined by  

a_n=a_1+\left(n-1\right)d

substituting a₁ = 3 and d = 4

a_n=4\left(n-1\right)+3

a_n=4n-4+3

a_n=4n-1

Therefore, an explicit rule for the  sequence

a_n=4n-1

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\bf \textit{difference of squares}&#10;\\ \quad \\&#10;(a-b)(a+b) = a^2-b^2\qquad \qquad &#10;a^2-b^2 = (a-b)(a+b)\\\\&#10;-------------------------------\\\\&#10;4x^2-9=0\implies 2^2x^2-3^2=0\implies (2x)^2-3^2=0&#10;\\\\\\\&#10;[(2x)-3][(2x)+3]=0\implies &#10;\begin{cases}&#10;2x-3=0\\&#10;2x=3\\&#10;x=\frac{3}{2}\\&#10;------\\&#10;2x+3=0\\&#10;2x=-3\\&#10;x=-\frac{3}{2}&#10;\end{cases}
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