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CaHeK987 [17]
3 years ago
13

What is the equation of the line passing through the points (2, –1) and (5, –10) in slope-intercept form?

Mathematics
1 answer:
BabaBlast [244]3 years ago
5 0

slope formula

-10--1/5-2

-9/3

-3

point slope form

y--1=-3(x-2)

y+1=-3x+6

y=-3x+5

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PLEASE NEED HELP ASAP IM GIVING ALL MY POINTS THIS SHOULD BE A EASY QUESTION.​
faust18 [17]

Answer:

  1. Function 1 is not a function.
  2. The domain and range of the first function respectively are \text{ \{-3, 0, 1, 5\}} and \text{ \{-4, -2, -1, 1, 3\}}.
  3. Function 2 is a function.
  4. The domain and range of the second function respectively are \text{ \{-2, -1, 0, 1, 2\}} and \text{ \{-7, -2, 1\}}.

Step-by-step explanation:

In math, every function has a domain and a range.

  • The domain of the function is all of the x-values for which the function is true. These can be found on the x-axis for every position at which the function exists or crosses the x-axis.
  • The range of the function is all of the y-values for which the function is defined. The range can be found in the same manner as the domain - for every y-value at which the function exists, it is apart of the range.

Therefore, with this information given to us, we need to also know about coordinate pairs. Coordinate pairs are written in (x, y) form.

Functions are classified in four ways:

  1. One-to-one functions: Functions are considered to be one-to-one functions if there are unique y-values (no y-values are repeated) and there is one x-value for every one y-value.
  2. Onto functions: Functions are considered to be onto functions if there are unique x-values. These x-values cannot repeat, but different x-values can be connected to the same y-values.
  3. Both one-to-one & onto: Functions are considered both one-to-one and onto when there is exactly one x-value for every one y-value.
  4. Neither one-to-one or onto: Functions are considered to be neither an one-to-one function or an onto function when they have two or more of the same y-values assigned to the same x-values. A function cannot exist if y-values are duplicated on a x-value.

Finally, the domain and range should be written in ascending order. Therefore, the lowest number should be written first in the domain and the highest number should be written last.

<u>Function 1</u>

We are given the function: \text{ \{(-3, 3)}, (1, 1), (0, -2), (1, -4), (5, -1) \} }.

Using the information above, we can pick out our x and y-values from the function.

Values of Domain: -3, 1, 0, 1, 5

Values of Range: 3, 1, -2, -4, -1

Now, we need to arrange these in ascending order.

Domain Rearranged: -3, 0, 1, 1, 5

Range Rearranged: -4, -2, -1, 1, 3

Using these values, we can see what values we have.

For x-values:

x = -3: 1 value

x = 0: 1 value

x = 1: 2 values

x = 5: 1 value

For y-values:

y = -4: 1 value

y = -2: 1 value

y = -1: 1 value

y = 1: 1 value

y = 3: 1 value

Therefore, we can begin classifying this function. Because we have all separate y-values, we have a function. However, we have two of the same x-value, so we have an onto function.

Now, we can create our domain and range in the set. We use the same formatting given for the first function. We list the values in ascending order and list them in brackets to show that they are apart of a set.

The domain values are the x-values, so they are \text{ \{-3, 0, 1, 5\}}.

The range values are the y-values, so they are \text{ \{-4, -2, -1, 1, 3\}}.

Therefore, the domain and range for function one are defined, but this is not a function. Because the x-values repeat, it cannot be a function.

<u>Function 2</u>

We are given a table of values that needs to be translated into the set notation. This makes it easier to identify the values. We are given x-coordinates in the top row and y-coordinates in the bottom row. And, the table is set up to where the x-value directly above the y-value makes a coordinate pair. Using this, we can create the set function.

The set function is \text{ \{(-2, -7), (-1, -2), (0, 1), (1, -2), (2, -7)\}}.

Now, we can use the same method as above to pick out the x and y-values and reorder them to be from least to greatest.

Values of Domain: -2, -1, 0, 1, 2

Values of Range: -7, -2, 1, -2, -7

Now, we rearrange these.

Domain Rearranged: -2, -1, 0, 1, 2

Range Rearranged: -7, -7, -2, -2, 1

Now, we can check how many times the function presents each coordinate.

For x-values:

x = -2: 1 value

x = -1: 1 value

x = 0: 1 value

x = 1: 1 value

x = 2: 1 value

For y-values:

y = -7: 2 values

y = -2: 2 values

y = 1: 1 value

Now, we can classify the function. The x-values are unique, but the y-values are repeated. Therefore, because the x-values are assigned to one y-coordinate and they are unique, this is not an one-to-one function. Additionally, it cannot be an onto function because the y-values are not unique - they are repeated. Therefore, it is neither an one-to-one function or an onto function. If this function were graphed, it would actually reveal a parabola. However, it is still a function.

The domain values are the x-values, so they are \text{ \{-2, -1, 0, 1, 2\}}.

The range values are the x-values, so they are \text{ \{-7, -2, 1\}}.

8 0
2 years ago
4. Owen and his family are discussing how to pay for his college education. The cost of tuition at the college that Owen wants t
MrMuchimi

Answer:

400

Step-by-step explanation:

12000 X 60%=7200-parents

12000-7200=4800-owen

4800/12=400 is what owen will save monthly

6 0
3 years ago
What is the slope of a line that is perpendicular to the line represented by the equation y=3/4x-1/2?
kherson [118]
The answer is:   " - (4/3) " .
____________________________________
Explanation:
____________________________________
The original equation given has a slope of (3/4).

Note:  We know this since the equation for the slope of the line is written in "slope-intercept form" ; also known as: "point-slope form";  that is:

  " y = mx + b " ;  in which "m" (the coefficient of "x") is the slope.
____________________________________________________
The slope of a line PERPENDICULAR to an equation, when written in "slope-intercept form", is the "negative reciprocal" of the slope of the original line.

Hence, the negative reciprocal of "(3/4)"  is:  "-(4/3)" .
____________________________________________________
5 0
3 years ago
One afternoon, a student who is 5 feet 4 inches tall measured shadows to find the height of a telephone pole. The student's shad
Setler79 [48]

Answer:

19.9875 feet

Step-by-step explanation:

The formula is given as:

Shadow of the student/Height of the student = Shadow of the telephone pole/Height of the telephone pole.

1 inch = 0.0833 feet

Shadow of the student = 5ft

Height of the student = 5 feet 4 inches

4 inches to feet

= 4 × 0.0833 feet

= 0.33 feet

Hence: Height of the student = 5 + 0.33 = 5.33 feet

Shadow of the telephone pole = 18 feet 9 inches long

9 inches to feet

= 9 × 0.0833 feet

= 0.75 feet

Hence: Shadow of the telephone pole = 18 + 0.75 = 18.75 feet

Height of the telephone pole= x

Therefore:

5/5.33 = 18.75/x

Cross Multiply

5x = 5.33 × 18.75

x = 5.33 × 18.75/5

x = 19.9875 feet

The height of the telephone pole = 19.9875 feet

4 0
3 years ago
Dusty won $125,000 on who wants to be a zillionaire? Game show. He decides to place the money into an account that earns 6.25% i
docker41 [41]

Answer:

kmlk

Step-by-step explanation:

,m,m

4 0
3 years ago
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