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solmaris [256]
3 years ago
7

What points in the scatter plot are outliers?

Mathematics
2 answers:
nikdorinn [45]3 years ago
4 0
K& H are the outliers. Outliers just mean the ones farthest away from the other points or if you have a line going through points and there's a point that's either really high or below the line it's considered an outlier :)
Julli [10]3 years ago
3 0
X and h is the answer
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3 years ago
If UV ≅ UX and WX=23, what is VW?<br><br> VW =
expeople1 [14]

Answer: VW= 23

Step-by-step explanation:

Because UV  =  UX the bisector has to split it evenly therefor WX = VW

So the answer is 23!  Does this make sense?

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2 years ago
Which ordered pair would form a proportional relationship with the point graphed below?
nevsk [136]

Answer:

(90,60)

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3 years ago
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scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

<em>H</em>₀: The variance of speeds does not exceeds 75 (mph)², i.e. <em>σ</em>² ≤ 75.

<em>Hₐ</em>: The variance of speeds exceeds 75 (mph)², i.e. <em>σ</em>² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, <em>α</em> = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}

    =\frac{(55-1)\times 94.7}{75}\\\\=68.184

The test statistic value is, 68.184.

Decision:

cal.\chi^{2}=68.184

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

7 0
3 years ago
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puteri [66]
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