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2 years ago

What points in the scatter plot are outliers?

Mathematics

2 answers:

nikdorinn [45]2 years ago

4 0

K& H are the outliers. Outliers just mean the ones farthest away from the other points or if you have a line going through points and there's a point that's either really high or below the line it's considered an outlier :)

Julli [10]2 years ago

3 0

X and h is the answer

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Find the value of x. Write your answer as a simplified radical if necessary.

Andreas93 [3]

Answer:

x=5

Step-by-step explanation:

The right angle opposite is the hypotenuse

The 30° is the opposite

SohCahToa

Soh = Sin because you got Opposite and Hypotenuse (because you're trying to find the side, you'd do the opposite of dividing, which is times)

10×sin(30)=5

3 0

2 years ago

When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F

aleksandr82 [10.1K]

Let $x$ be the unknown number. So, three times that number means $3x$ , and the square of the number is $x^2$

We have to sum 528 and three times the number, so we have $528+3x$

Then, we have to subtract this number from $x^2$ , so we have

$x^2-(3x+528)$

The result is 120, so the equation is

$x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0$

This is a quadratic equation, i.e. an equation like $ax^2+bx+c=0$ . These equation can be solved - assuming they have a solution - with the following formula

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

If you plug the values from your equation, you have

$x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}$

So, the two solutions would be

$x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27$

$x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24$

But we know that x is positive, so we only accept the solution $x = 27$

6 0

3 years ago

(-1/9) ÷ 6/7 =<br><br> Help<br> Me<br> Pls<br> :)

german

Answer:

I believe your answer is -7/54

3 0

2 years ago

Read 2 more answers

Write the expression in terms of sin x and cos x only. sin(2x)+cos(3x)

BartSMP [9]

Sin2x=2sinxcosx, cos2x=1-2sin^2x
sin(2x)+cos(3x)=2sinxcosx+cos(x+2x)
cos(x+2x)=cosx(1-2sin^2(x))-sinx2sinxcosx
sin(2x)+cos(3x)=2sinxcosx(1-sinx)+cosx(1-2sin^2(x))

5 0

3 years ago

Read 2 more answers

QUESTION in the diagram below the following are rectangles. ACEG ;BCDJ ; JDEF and HJFG is a square AB =AH = x ;BC=5 ; HG=3 Area

White raven [17]

The area of the rectangle ACEG is the amount of space on it, and the area of square HJFG is 9 square units

<h3>How to determine the area of the figures?</h3>

The area of a rectangle is:

Area = Length * Width

The area of a square is:

Area = Length * Length

From the question, the given parameters are:

AB =AH = x ;

BC=5;

HG=3

This means that the area of square HJFG is:

Area = HG * HG

Area = 3 * 3

Area = 9

<em>Note that the other areas cannot be calculated because the question is incomplete</em>

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