The slant height of a cone with lateral surface are of 19.2π inches squared and radius of 2.4 inches is 8 inches.
<h3>Lateral surface area of a cone</h3>
The formula for the lateral surface area of a cone is described as follows:
Lateral area = πrl
where
- r = base radius
- l = slant height
Therefore,
Lateral area = 19.2π inches²
r = 2.4 inches
Lateral area = π × 2.4 × l
19.2π = 2.4πl
divide both sides by 2.4π
l = 19.2π / 2.4π
l = 8 inches
learn more on cone here: brainly.com/question/27170515
Answer:
Triangles QUT and SVR are congruent because the defining two sides and an included angle of triangles QUT and SVR are equal
Step-by-step explanation:
Here we have QT = SR and
QV = SU
Therefore,
QT = √(UT² + QU²)........(1)
RS = √(VS² + RV²)..........(2)
Since QS = QU + SU = QV + VS ∴ QU = VS
Therefore, since SR = QT and QU = VS, then from (1) and (2), we have UT = RV
Hence since we know all sides of the triangles QUT and SVR are equal and we know that the angle in between two congruent sides of the the triangles QUT and SVR that is the angle in between sides QU and UT for triangle QUT and the angle in between the sides RV and VS in triangle SVR are both equal to 90°, therefore triangles QUT and SVR are congruent.
I did these about 1 year ago but i think you subtract the 6 from 30 and then divide by 4, and that gives u 24/4 which is 6. i barely barely remember some so
Answer:
If your solving for x on the first one it’s x =−5/2y+8
If your solving for y on the second one it’s y =−4x+3
Step-by-step explanation:
Answer:
y = (5/9)x + 2
Step-by-step explanation:
Slope intercept form is
y = mx + b then plug in the values
y = (5/9)x + 2
