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4 years ago

Can 0.525252 be written as a fraction why or why not

Mathematics

2 answers:

Marrrta [24]4 years ago

8 0

Any decimal can be a fraction
.525252/1 is a fraction

horsena [70]4 years ago

3 0

That number can be written in fraction form if you approximate it such as 0.52525252 is approx. 0.53 which would be ~ 53/100.

Or you can find the exact numbers/ratio that will yield that exact repeating number.

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100 POINTS ANSWER PLEASE URGENT PLEASE DUE IN 8 mins

AnnZ [28]

Answer:

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Second image: 8.62%

Third image: -43/2

Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

A particular variety of watermelon weighs on average 20.4 pounds with a standard deviation of 1.23 pounds. Consider the sample m

love history [14]

Answer:

a) The expected value of the sample mean weight is 20.4 pounds.

b)The standard deviation of the sample mean weight is 0.123.

c) There is a 14.46% probability the sample mean weight will be less than 20.27.

d) This value is $c = 20.6153$ .

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A particular variety of watermelon weighs on average 20.4 pounds with a standard deviation of 1.23 pounds. This means that $\mu = 20.4, \sigma = 1.23$

Consider the sample mean weight of 100 watermelons of this variety. This means that $n = 100$ .

a. What is the expected value of the sample mean weight? Give an exact answer.

By the Central Limit Theorem, it is the same as the mean of the population. So the expected value of the sample mean weight is 20.4 pounds.

b. What is the standard deviation of the sample mean weight? Give your answer to four decimal places.

By the Central Limit Theorem, that is:

$s = \frac{\sigma}{\sqrt{n}} = \frac{1.23}{\sqrt{100}} = 0.123$

The standard deviation of the sample mean weight is 0.123.

c. What is the approximate probability the sample mean weight will be less than 20.27?

This is the pvalue of Z when $X = 20.27$ .

Since we are working with the sample mean, we use $s$ instead of $\sigma$ in the Z score formula

$Z = \frac{X - \mu}{s}$

$Z = \frac{20.27 - 20.4}{0.123}$

$Z = -1.06$

$Z = -1.06$ has a pvalue of 0.1446.

This means that there is a 14.46% probability the sample mean weight will be less than 20.27.

d. What is the value c such that the approximate probability the sample mean will be less than c is 0.96?

This is the value of $X = c$ that is in the 96th percentile, that is, it's Z score has a pvalue 0.96.

So we use $Z = 1.75$

$Z = \frac{X - \mu}{s}$

$1.75 = \frac{c - 20.4}{0.123}$

$c - 20.4 = 0.123*1.75$

$c = 20.6153$

This value is $c = 20.6153$ .

6 0

3 years ago

Please help me with this

spin [16.1K]

Answer:

the answer is 60

Step-by-step explanation:

4*5*3=60

4 0

3 years ago

Se cocina una pizza de 20 cm de radio, en su interior se coloca al azar 12 piezas de salami

Furkat [3]

Answer:

The area of cheese is 388π cm.

Step-by-step explanation:

Given that,

Radius of pizza = 20 cm

Number of pieces = 12

Radius of circle = 1 cm

We need to calculate the area of pizza

Using formula of area

$A=\pi\times r^2$

Put the value into the formula

$A=\pi\times20^2$

$A=400\pi\ cm^2$

We need to calculate the area of circle

Using formula of area

$A'=\pi\times r^2$

Put the value into the formula

$A'=\pi\times1^2$

$A'=\pi\ cm^2$

Now, we multiply the result by 12 because they are 12 salamis.

So. the area of salamis will be

$A'=12\pi\ cm^2$

We need to calculate the area of cheese

The total area of the pizza and subtract the area of the salamis

$A''=A-A'$

Put the value in to the formula

$A''=400\pi-12\pi$

$A=388\pi\ cm^2$

Hence, The area of cheese is 388π cm.

6 0

3 years ago

A population of insects increases according to the law of exponential growth. After 2 days of growth there are 100 insects. Afte

Fantom [35]

Answer:

I think its A so hope this helps

3 0

3 years ago