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Answer: 0.4758
Step-by-step explanation:
Given : Mean : 
Standard deviation : 
Also, the new population of pilots has normally distributed .
The formula to calculate the z-score :-

For x=130 lb .

For x=171lb.

The p-value =

Hence, the required probability : 0.4758
Answer:
Please see attachment
Step-by-step explanation:
Please see attachment