Answer: Segment BC of image is parallel to segment AD of image.
Step-by-step explanation:
Given: Quadrilateral ABCD is the result of a translation of quadrilateral EFGH.
Segment EF is parallel to segment HG in the pre-image.
Since translation is a rigid transformation which preserves the side-lengths and angles of the original figures.
Therefore, all the segments of the image figure are parallel to correspondent segments of the original figure.
Segment AD of <em>image</em> is parallel to segment HG in the <em>pre-image.</em>
Segment BC of <em>image</em> is parallel to segment EF in the <em>pre-image.</em>
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Hence, if Segment EF is parallel to segment HG in the pre-image.
⇒ Segment BC of image is parallel to segment AD in image.
