Answer:
Step-by-step explanation:
Initially, the the total quantity of the mixture = 10 lb
In which dried fruit = 25% of 10 lb = 2.5 lb
Since, according to the question, employee adds x lb of Active Mix, which contains 40% dried fruit by weight.
So, the total mixture after addition =( 10+ x ) lb
In which total dried fruit= 2.5 lb+ 40% of x= (2.5+ 0.4x) lb
So the percentage of the dried fruit in the new mixture =( quantity of dried fruit in the mixture/ total quantity ). 100
= ![\frac{2.5 + 0.4x}{10+x} .100](https://tex.z-dn.net/?f=%5Cfrac%7B2.5%20%2B%200.4x%7D%7B10%2Bx%7D%20.100)