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Serggg [28]
3 years ago
5

Can someone please help me out

Mathematics
1 answer:
Gemiola [76]3 years ago
7 0

Answer:

c

Step-by-step explanation:

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If Pentagon ABCDE was dilated to create Pentagon A'B'C'DE', what rule was used?
svetlana [45]

Answer:

<em>B</em> (x,y) \rightarrow \left(\frac{5}{2}x,\frac{5}{2}y\right)

Step-by-step explanation:

<u>Dilations</u>

Given a point A(x,y) and a scale factor k the dilated image of A, called A' is calculated as A'=(kx,ky), assuming the same scale factor is applied in both axes.

The pentagon ABCDE was dilated to create pentagon A'B'C'D'E'. To find the dilaton rule used, we must find two clear points where the coordinates of both axes can be easily read from the graph.

Point C(-2,0) maps to C'(-5,0). This gives us the scale factor for the x-axis of -5/(-2)= 5/2.

The y-coordinate of E is 2 and the y-coordinate of E' is 5. This gives us the same scale factor for the y-axis of 5/2.

Thus, the rule to dilate the pentagon is:

B \mathbf{(x,y) \rightarrow \left(\frac{5}{2}x,\frac{5}{2}y\right)}

5 0
3 years ago
What is the lcm of 81 and 17?​
algol [13]

Answer:

1377

Step-by-step explanation:

The least common multiple (LCM) of two or more non-zero whole numbers is the smallest whole number that is divisible by each of those numbers. In other words, the LCM is the smallest number that all of the numbers divide into evenly.

3 0
2 years ago
Lalo has 1,500 minutes per month on his cell phone plan. How many more minutes can he use if he has already talked for 785 minut
Mandarinka [93]
He can use 715 minutes for the rest of the month.
7 0
2 years ago
Read 2 more answers
Which expression is equivalent to (8^2)^-4
xz_007 [3.2K]

Answer:

C: \frac{1}{8*8*8*8*8*8*8*8}

Step-by-step explanation:

a^{-n} = \frac{1}{a^n}

Since a = 8^2 :

(8^2)^{-n} = \frac{1}{(8^2)^n} =\frac{1}{8^{2n}}

Since n = 4 :

(8^2)^{-4} =\frac{1}{8^{2*4}}=\frac{1}{8^{8}}=\frac{1}{8*8*8*8*8*8*8*8}

6 0
2 years ago
Find equivalent ways to rewrite the expression 6a^8÷3a^4​
solong [7]

Answer:

6a^8/3a^4= (6/3)= 2

a^8/a^4= a^4

2a^4

(6/3)(a^8/a^4)= 2a^4

(6/3)(a^(8-4))= 2a^4

Step-by-step explanation:

5 0
3 years ago
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