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anyanavicka [17]
4 years ago
14

Forgot how to it needing help??

Mathematics
1 answer:
katrin [286]4 years ago
4 0
18.
AC = 39
This means that AB + BC = AC
2x - 8 + x + 17 = 39
3x + 9 = 39
3x = 30
x = 10
Then, insert the x into both AB and BC.
AC = 2(10) - 8
AC = 20 - 8
AC = 12
BC = (10) + 17
BC = 27

19.
DG = 60
4x - 3 + 2x + 21 = 60
6x + 18 = 60
6x = 42
x = 7
DO = 4(7) - 3
DO = 28 - 3
DO = 25
OG = 2(7) + 21
OG = 14 + 21
OG = 35
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svetoff [14.1K]
The answer to your question is 8mi. I just divide the circumference by pi to find your diameter.
8 0
3 years ago
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Five rational numbers between -2/5 and 1/5
Vsevolod [243]

Answer:

-2/5 × 3/3 = -6/15

1/5 × 3/3 = 3/15

Five rational numbers in between are : -1/3, -4/15, -1/5, -2/15, -1/15

6 0
3 years ago
A water faucet runs at a rate of 4/5 gallon per 1/5 minute. What is the unit rate of the faucet? *
vodomira [7]

Answer:

<h2>4gallons per minute</h2>

Step-by-step explanation:

Step one:

the unit rate is the amount of water per unit of time

Given data

4/5 gallon to decimal= 0.8gallon

1/5 minute decimal= 0.2 minute

We are told that 0.8 gallons run in 0.2 minute

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cross muliply we have

x=0.8/0.2

x=4

this means that in one minutes 4gallons will run in the faucet

The unit rate is 4gallons per minute

6 0
3 years ago
Identify the degree of the polynomial 8x^3y^2 – 10xy + 4x^2y^2 + 3.
Anastaziya [24]
When the polynomial has more than one variable you have to sum the exponents of the variables for every monomial. The largest sum is the order of the polynomial.

Here:

momomial   sum of the exponents
8x^3y^2       3 + 2  = 5
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3 0
3 years ago
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If W, V, and U are the midpoints of triangle SRT, find SR.<br>A.1.7B.2.3C.3.4D.4.6  
liq [111]

ANSWER


The correct answer is 4.6


EXPLANATION

|SR|=|RU|+|SU|


Since U is the midpoint of |RS|,

|RU|=2.3=|SU|

U being the midpoint of RS means, it is in the middle of R and S.

So if from R to U is 2.3, then from U to S is also 2.3.

This is an implication that


|SR|=2.3+2.3


|SR|=4.6


See diagram in the attachment.


5 0
3 years ago
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