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swat32
3 years ago
14

A water faucet runs at a rate of 4/5 gallon per 1/5 minute. What is the unit rate of the faucet? *

Mathematics
1 answer:
vodomira [7]3 years ago
6 0

Answer:

<h2>4gallons per minute</h2>

Step-by-step explanation:

Step one:

the unit rate is the amount of water per unit of time

Given data

4/5 gallon to decimal= 0.8gallon

1/5 minute decimal= 0.2 minute

We are told that 0.8 gallons run in 0.2 minute

                      then x gallon will run in 1 minute

cross muliply we have

x=0.8/0.2

x=4

this means that in one minutes 4gallons will run in the faucet

The unit rate is 4gallons per minute

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Answer:  do you still need this and do you want to be friends

Step-by-step explanation:

5 0
3 years ago
Circles with centers $(2,1)$ and $(8,9)$ have radii $1$ and $9,$ respectively. the equation of a common external tangent to the
snow_tiger [21]

For the complete understanding of the solution of this question please check the two attached files too.

Let us begin.

There are two circles given to us. Let us call them C1 and C2. Now, we know that C1 has centre at (2,1) and has a radius, say, r_{1} of 1. We also know that C2 has centre at (8,9) and has a radius, say, r_{2} of 9.

We know from coordinate geometry that of the center (a,b) and the radius, r of a circle are given then, the equation of the circle is given by:

(x-a)^2+(y-b)^=r^2

Using this formula and applying it to both the circles, we will get the equations of the two circles to be:

C1:(x-2)^2+(y-1)^2=1^2

or (x-2)^2+(y-1)^2-1=0 (subtracting both sides by 1)

and

C2: (x-8)^2+(y-9)^2=9^2

or (x-8)^2+(y-9)^2-81=0 (subtracting both sides by 9^2 which is 81).

Now, we know that, at if the circles have a common external tangent such that m or in other words m is negative then we must be having the condition that the circles touch each other as is evident from the first diagram.

All we need to do now is to equate the two equations of the circles C1 and C2 and solve for y in terms of x.

That will give us:

(x-2)^2+(y-1)^2-1=(x-8)^2+(y-9)^2-81=0

Solving this we get:

4y=-3x+15

y=-\frac{3}{4}x +\frac{15}{4}

y=-0.75x+3.75

This is the required equation of the tangent line and thus, as we can see b=\frac{15}{4} or 3.75

8 0
3 years ago
Rajan needs 1 liter of 15% hydrochloric acid solution for an experiment. He checks his storage cabinet, but he only has a 5-lite
Delvig [45]

Answer:

  1. <em>0.75</em><em> liters of 5% hydrochloric acid solution </em>
  2. <em>0.25</em><em> liters of 45% hydrochloric acid solution.</em>

Step-by-step explanation:

Let us assume that, x liters of the 5% hydrochloric acid and y liters of the 45% hydrochloric acid solutions are combined.

As Rajan need total of 1 liter of solution, so

x+y=1

i.e x=1-y --------------------1

As Rajan needs 5% hydrochloric acid and 45% hydrochloric acid to make a 1 liter batch of 15% hydrochloric acid, hence acid content of the mixture of two acids will be same as of the final one, so

0.05x+0.45y=1\times 0.15

i.e 5x+45y=15 -------------2

Putting value of x from equation 1 in equation 2,

\Rightarrow 5(1-y)+45y=15

\Rightarrow 5-5y+45y=15

\Rightarrow 5+40y=15

\Rightarrow 40y=15-5=10

\Rightarrow y=0.25

Putting the value of y in equation 1,

x=1-0.25=0.75

Therefore, Rajan must use 0.75 liters of 5% hydrochloric acid solution and 0.25 liters  of 45% hydrochloric acid solution.

4 0
4 years ago
PLEASE HELP ME SOLVE THIS ASAP WITH WORK!!
Vlad [161]

Answer:

6

Step-by-step explanation:

  1. If you multiply a number from the big polygon by 2/3s, you will get the corresponding number on the small polygon. For example, 6 × 2/3 = 4
  2. To find x, find the corresponding number on the big polygon and multiply it by 2/3s. The number on the big polygon is 9. 9 × 2/3 = 6

I hope this helps!

5 0
3 years ago
For what value of x is line a parallel to line b?<br><br> Enter your answer in the box.<br> X=
goblinko [34]

Answer:

x = 20

Step-by-step explanation:

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(5x + 15)° = 115° add like terms

5x = 100

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4 0
3 years ago
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