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3 years ago

0:4

Mathematics

1 answer:

Margaret [11]3 years ago

8 0

Answer:

3 > x

Step-by-step explanation:

-10 + 8x < 6x - 4

Subtract 8x from each side

-10 + < -2x - 4

Add 4 to each side

-6 < -2x

Divide each side by -2 remembering to flip the inequality

-6/-2 > -2x/-2

3 > x

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A product is now £50, the product was reduced by 20%, what was the original price

olga nikolaevna [1]

the original price is "x", or 100%.

but we know that if we reduce "x" by 20%, namely 100% - 20% = 80%, the 80% of "x" is really £50, what is "x" or the 100% anyway?

$\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} x&100\\ 50&80 \end{array}\implies \cfrac{x}{50}=\cfrac{100}{80}\implies \cfrac{x}{50}=\cfrac{5}{4}\implies 4x=250 \\\\\\ x=\cfrac{250}{4}\implies x=62.5$

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3 years ago

SUPER EASY MATH PROBLEM IM JUST DUMB, WILL MARK BRAINLIEST. PLEASE HELP

worty [1.4K]

Answer:

m<1 = 105°

m<2 = 75°

very simple explanation:

a and b are perpendicular. line t intersects these perpendicular lines. the given 75° is, in short, an intersect of a line, which is 180°. 75-180=105. angles 1 and 2 are duplicates of what is shown

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3 years ago

What is the interquartille range of the given data set

IrinaK [193]

Answer: B. 9

Step-by-step explanation:

First, find the median of the data set. This set has an even number of points, so find the average between the two middle points: 18 and 19. 18+19 = 37. 37/2 = 18.5. <em>The median is 18.5.</em>

Now, to find the lower quartile, find the median of the lower half of the data set {11, 12, 14, 15, 18}. The number in the middle is 14. <em>The lower quartile is 14.</em>

To find the upper quartile, find the median of the upper half of the data set {19, 21, 23, 25, 55}. The number in the middle is 23. <em>The upper quartile is 23.</em>

To find the interquartile range, subtract the lower quartile from the upper quartile. 23-14 = 9. <em>The interquartile range is 9.</em>

3 0

2 years ago

A shipping container will be used to transport several 100-kilogram crates across the country by rail. The greatest weight that

snow_tiger [21]

Answer:

$12800 + 100x \le 24000$

A maximum of 112 number of 100 - kilograms can be loaded in the container.

Step-by-step explanation:

Given that:

Weight of each crate = 100 kg

The greatest weight that can be loaded in the container = 24000 kg

Weight already loaded in the container = 12800 kg

To find:

The inequality to determine the value $x$ i.e. number of 100 - kilograms that can be loaded in the shipping container?

Solution:

Weight already loaded = 12800 kg

Let the number of 100 - kilograms that can be loaded in the container = $x$

Weight of $x$ = 100 $x$ kg

This combined weight nor be greater than the capacity of the container.

OR we can say, it must be lesser than or equal to greatest weight that can be loaded into the container.

$12800 + 100x \le 24000$

$100x \le 24000 - 12800\\\Rightarrow 100x \le 11200\\\Rightarrow x \le 112$

i.e. a maximum of <em>112</em> number of 100 - kilograms can be loaded in the container.

5 0

3 years ago

Anya makes a scale drawing of a bug. The scale of the drawing’s length to the actual bug’s length is 2 inches: 1/8 inch. The act

ioda

<h2>Hello!</h2>

The answer is: The Anya's drawing is 6 inches long.

Have a nice day!

To solve this problem, we need to consider the drawing's length with respect to the actual bug's size, so, the scale factor is:

$2in:\frac{1}{8}in\\\\2x(in):\frac{3}{4}in$

So, how long is Anya's drawing of the bug?

We can find it, using the following equation:

$(2x)in=\frac{2in*\frac{3}{4}in}{\frac{1}{8}in}=\frac{\frac{6}{4}in}{\frac{1}{8}in}=\frac{\frac{3}{2}in }{\frac{1}{8}in}\\\\(2x)in=\frac{\frac{3}{2}in }{\frac{1}{8}in }=\frac{3}{2}in*\frac{8}{1}in=12in^{2}\\\\(2x)in=12in^{2} \\\\x=\frac{12in^{2} }{2in}=6in$

Hence, the Anya's drawing is 6 inches long.

Have a nice day!

7 0

3 years ago