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KengaRu [80]
2 years ago
7

How do you use proportions to solve percent problems​

Mathematics
1 answer:
exis [7]2 years ago
7 0

Answer:

Step-by-step explanation:

EXAMPLE #1:

What number is 75% of 4?   (or   Find 75% of 4.)

The PERCENT always goes over 100.

   (It's a part of the whole 100%.)

4 appears with the word of:

   It's the WHOLE and goes on the bottom.

A proportion showing one fraction  with PART as the numerator and 4 as the denominator equal to another fraction with 75 as the numerator and 100 as the denominator.

We're trying to find the missing PART (on the top).

In a proportion the cross-products are equal:   So 4 times 75 is equal to 100 times the PART.

The missing PART equals 4 times 75 divided by 100.

(Multiply the two opposite corners with numbers; then divide by the other number.)

4 times 75 = 100 times the part

300 = 100 times the part

300/100 = 100/100 times the part

3 =   the part

A proportion showing the denominator,  4, times the diagonally opposite 75; divided by  100.

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Nikitich [7]

Answer:

y= -a*x + 12

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>b</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>b</u>

Step-by-step explanation:

ax+by=12 (subtract "ax" from both sides so that the one on the left will become zero and we will have "by" )

by= -ax+12(divide both side by "by" so that we will have the equation as "y=mx+b")

finally the result will be:

y= -a*x + 12

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