The sum of 4 consecutive odd integers is 336. Find the largest integer. Let x, x+2, x+4, x+6 be the 4 integers. 81+6=87 ans.
Answer:
below
Step-by-step explanation:
-3x² + 6x + 6 = 0
x = (-b±√(b²-4ac))/2a
x = (-6±√(36 - 4(-3)(6)))/2(-3)
x = (-6±√108)/-6
x = 1 ± √3
The negative solution is not reasonable for he threw it forwards
Answer:

Step-by-step explanation:
We begin with 
First, we can convert this decimal into a fraction

Now, we can simplify the denominator of the fraction

Next, we can remove the fraction by rewriting the fraction with a negative power.

Lastly, we can remove the parenthesis by multiplying the powers together.

This means that 
When multiplying, you add indices
so it's 5^15
when dividing, you minus indices just fyi
<span>f(x)=2x+1 and g(x)=x^2-7
(f+g)(x) = </span>2x + 1 + x^2 - 7
(f+g)(x) = x^2 + 2x - 6
answer
x^2 + 2x - 6