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UNO [17]
4 years ago
6

Why is it important to consider scale when graphing inequalities?

Mathematics
1 answer:
Olegator [25]4 years ago
6 0

Because to get a straight line you need a scale. Otherwise you will not be able to graph a straight line.

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Solve the system using elimination.<br> 2x + 3y = -2<br> 3x - 6y = 18
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dd the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.

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Jeff paid $38 for 9 1/2 yards of lumber what was the price for one a yard
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IgorLugansk [536]

Answer :

Option B

Step by step explanation :

As we can see in figure, Triangle is right angled at A

In ∆ABC

By Pythagoras theorem,

BC² = AC² + AB²

=> BC² = (3)² + (4)²

=> BC² = 9 + 16

=> BC² = 25

=> BC = 5 cm

We know,

\:\mathsf{Area \:of\: triangle}=\:\mathsf{\frac{1}{2}\: x\: base\: x\: height}

Here,

base = AC = 3cm

height = AB = 4cm

=> \:\mathsf{Area \:of\: triangle}=\:\mathsf{\frac{1}{2} \:x\: 3cm\: x\:4cm}

=> \:\mathsf{Area \:of\: triangle\: = \:3cm\: x\: 2cm}

=> \:\bf\boxed{Area \:of\: triangle\: = \:6cm²}

As BC = DE

And then BD = EC

it shows the property of rectangle

So BD = 6 cm

Now,

\:\mathsf{Area \:of\: rectangle\: =\: length \:x\: width}

=> Area of rectangle = 6cm x 5cm

=> \:\bf\boxed{Area\: of\: rectangle\: = \:30cm²}

Now,

Area of the figure = Area of rectangle + Area of triangle

=> Area of the figure = 30cm² + 6cm²

=> \:\bf\boxed{Area\: of\: the\: figure\: = \:36cm²}

Therefore, <u>option B</u> is the correct answer for this question.

3 0
3 years ago
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Olin [163]
5. 12
6. just add all of the numbers up, it would be 32
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