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labwork [276]
3 years ago
5

Show that the given curve c(t) is a flow line of the given velocity vector field F(x, y, z).

Mathematics
1 answer:
liq [111]3 years ago
6 0

Answer:

a) c'(t) = (2 Cos(t), -2 Sin(t), 9e^t)

b) c'(t) = (2 Cos(t), -2 Sin(t), 9e^t)

Step-by-step explanation:

We are given in the question:

c(t) = (2 Sin(t), 2 Cos(t), 9e^t)

F(x,y,z) = (y, -x, z)  

a) c'(t)

We differentiate with respect to t.

c'(t) = (2 Cos(t), -2 Sin(t), 9e^t)

b) F(c(t))

This is a composite function.

F(c(t)) = F(2 Sin(t), 2 Cos(t), 9e^t)

= (2 Cos(t), -2 Sin(t), 9e^t)

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Please If you can see if you can help on some of my questions!!!!
kvv77 [185]
PQ // BC 

then

Angle P = Angle B, A is common angle the two triangles are similar

AP/AB  = AQ/AC

8/18 = 12/ AC

AC = 12 * 18/8 = 27 (your ans: D)

AQ + QC = AC

QC = AC - AQ = 27 - 12 = 15 (if it was required) 

tan60 = y/8

y = s tan60 = 8sqrt(3)  (B)

Next time, post each question separately. 


6 0
2 years ago
I(1, 1) and J (-3,-3)<br> Find the midpoint of the line segment
Pavlova-9 [17]
The Answer is (-1,-1)
4 0
3 years ago
Math homework due tomorrow
Margarita [4]
5.5-3b = 2b-6.25 5.5+6.25 = 2b+3b 11.75 = 5b 11.75/5 = 5b/5 2.35 = b
8 0
3 years ago
the product of 2 consecutive positive into is 1,332. Explain how you can write and solve a quadratic equation to find the value
Dominik [7]
Let the smaller one is x so the larger is x+1 
x(x+1)=1332 
x^2+x=1332 
x^2 +x -1332 =0 
(x - 36)(x + 37) =0
so x = 36 or x = -37
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8 0
3 years ago
Read 2 more answers
MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t
ioda

Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

Then you would get

                      l\lambda (w+2h) = w\lambda (l+2h) =  h\lambda (2w+2l)

You can get rid of \lambda from these equations and you would get

                         lw+2lh = lw+2wh =  2wh+2lh

And from those equations you would get

                                             l = w =2h

Now remember the original equation

                                    lw+2lh+2wh = 64

If we plug in what we just got, we would have

                                 l^{2} + l^{2} + l^2   =  64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}

                       

                                                 

7 0
3 years ago
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