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3 years ago

99.73-63.434 rounded to the nearest whole number

Mathematics

1 answer:

Bingel [31]3 years ago

6 0

<span>99.73-63.434 =
</span>36.296
Round this to the nearest whole number
= 36

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Which property of multiplication is shown? 3 * (5 * 7) = (3 * 5) * 7

kari74 [83]

Answer:

the associative property

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3 years ago

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AHarris Interactive survey for InterContinental Hotels & Resorts asked respondents, "When traveling internationally, do you

Sauron [17]

Answer:

a) There is a 27.89% probability that two will stick with their tour group.

b) There is a 41.81% that in at least two will stick with their tour group.

c) There is a 7.33% probability that none will stick with their tour group.

Step-by-step explanation:

For each responders, this question can only have two outcomes. Either they stick with their tour group, or they don't. So this means that we can solve this problem as binomial distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For these problems

The survey found that 23% of the respondents stick with their tour group, so $\pi = 0.23$ .

a. In a sample of six international travelers, what is the probability that two will stick with their tour group?

The sample has six travelers, so $n = 6$ .

We want P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{6,2}.(0.23)^{2}.(0.77)^{4} = 0.2789$

There is a 27.89% probability that two will stick with their tour group.

b. In a sample of six international travelers, what is the probability that at least two will stick with their tour group?

Either less than two stick with their groups, or at least two do. The sum of these probabilities is decimal 1.

$P(X < 2) + P(X \geq 2) = 1$

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{6,0}.(0.23)^{0}.(0.77)^{6} = 0.2084$

$P(X = 1) = C_{6,1}.(0.23)^{1}.(0.77)^{5} = 0.3735$

-----

$P(X < 2) = P(X = 0) + P(X = 1) = 0.2084 + 0.3735 = 0.5819$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5819 = 0.4181$

There is a 41.81% that in at least two will stick with their tour group.

c. In a sample of 10 international travelers, what is the probability that none will stick with the tour group?

Now our sample has 10 travelers, so $n = 10$ .

We want to find P(X = 0)

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{10,0}.(0.23)^{0}.(0.77)^{10} = 0.0733$

There is a 7.33% probability that none will stick with their tour group.

3 0

4 years ago

The 4th time of me posting this question

Vanyuwa [196]

Not clear crop it more

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3 years ago

What is 99 time 6<br><img src="https://tex.z-dn.net/?f=99%20%5Ctimes%206" id="TexFormula1" title="99 \times 6" alt="99 \times 6"

noname [10]

594 is the answer :)

3 0

3 years ago

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Need help with this questsion answer as a dollar amount

makkiz [27]

Answer:

100,000,000,000

Step-by-step explanation:

10^6 = 1,000,000. So one million computer programmers.

They're all making 10^5. So 100,000.

1,000,000 * 100,000, since every single one is making 100k.

Therefore, $100,000,000,000 is your answer.

Remember not to include the dollar sign!

8 0

4 years ago