Given: h(t) = 25 - a·t²
h(0.5) = 21
Find: t such that h(t) = 0
Solution: h(0.5) = 25 - a·0.5² = 21
25 - 21 = a/4
4·4 = a = 16
Then
h(t) = 25 - 16t²
We want h(t) = 0, so
0 = 25 - 16t²
16t² = 25
t² = 25/16 = (5/4)²
t = 5/4 = 1.25
It takes 1.25 seconds for the entire 25 ft drop.
Answer: y = -1,2x + 3.4
Step-by-step explanation:
y = ax + b
(2,1) => 1 = 2a + b (1)
(17,-17) => -17 =17a + b (2)
Using caculator Mode => 5 =>1
We get : a=- 1.2 , b = 3.4
=> y = -1.2x + 3.4
Answer:
nice
Step-by-step explanation:
Answer:
1.75
Step-by-step explanation:
0.009÷0.004-
=
2.25-0.5=
1.75