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2 years ago

Find the surface area of a cube with side length 6 1/2

2 answers:

5 0

To find the surface are youd have to multiply 6 1/2 by 6, because a cube has 6 total sides. so the answer would be 6•6.5 which equals 39

Scrat [10]2 years ago

5 0

The formula of the surface area of the cube is 6s^2. “S” stands for side length, and you square it to get the area of one side of the cube. Multiply that by 6 (6 identical faces on a cube) to get the answer. So 6 x (6.5 x 6.5) equals 253.5 or 253 1/2. Don’t forget units if the problem has included them.

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HELP++++++++++++++++++++++++

lys-0071 [83]

Answer:

ASA

ΔFGH ≅ ΔIHG ⇒ answer B

Step-by-step explanation:

* Lets revise the cases of congruence

- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and

including angle in the 2nd Δ

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ

≅ 2 angles and the side whose joining them in the 2nd Δ

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

leg of the 2nd right angle Δ

* Lets prove the two triangles FGH and IHG are congruent by on of

the cases above

∵ FG // HI and GH is transversal

∴ m∠FGH = m∠IHG ⇒ alternate angles

- In the two triangles FGH and IHG

∵ m∠FHG = m∠IGH ⇒ given

∵ m∠FGH = m∠IHG ⇒ proved

∵ GH = HG ⇒ common side

∴ ΔFGH ≅ ΔIHG ⇒ ASA

* ASA

ΔFGH ≅ ΔIHG

3 0

2 years ago

Ivan has 15 yards of green felt and 12 yards of blue felt to make 3 quilts if Ivan uses the same total number of yards for each

mixas84 [53]

Answer:

9 yards

Step-by-step explanation:

Let the length of each quilt be 'l'.

Given:

Length of green felt (g) = 15 yards

Length of blue felt (b) = 12 yards

Total number of quilts = 3

Now, the length of 3 quilts is given as:

$Total\ length=l+l+l=3l$ ----- (1)

As per question:

Total length = Length of green felt + Length of blue felt

Total length = $g+b$

$Total\ length=15+12=27$ --------- (2)

Now, comparing equations (1) and (2), we get:

$3l=27\\\\l=\frac{27}{3}\\\\l=9\ yards$

Hence, each quilt measures 9 yards in length.

3 0

2 years ago

X²+y²-6x+14y-1=0<br> and please show your work so I can learn

Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

$x^2 + y^2 -6x+14y-1=0$

We need to use the Quadratic Formula*

$x =\frac{-b+\sqrt{b^2}-4ac }{2a}$ , $\frac{-b-\sqrt{b^2} -4ac }{2a}$

Thus, given the problem:

$a = 1, b=-6, c=y^2+14y-1$

So now we just need to plug them in the Quadratic Formula*

$x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$ , $x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$

As you can see, it is a mess right now. Therefore, we need to simplify it

$x=\frac{6+2\sqrt{10-y^2-14y} }{2}$ , $x = \frac{6-2\sqrt{10-y^2-14y} }{2}$

Now that's get us to the final solution:

$x=3+\sqrt{10-y^2-14y}$ , $x=3-\sqrt{10-y^2-14y}$

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0

2 years ago

the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?

madam [21]

Answer:

About 0.6548 grams will be remaining.

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

$f(t)=a(r)^t$

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

$\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}$

One year has 365 days.

Therefore, the amount remaining after one year will be:

$\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548$

About 0.6548 grams will be remaining.

Alternatively, we can use the standard exponential growth/decay function modeled by:

$f(t)=Ce^{kt}$

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

$255=510e^{38k}$

Solving for k:

$\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)$

Thus, our function is:

$f(t)=510e^{t\ln(.5)/38}$

Then after one year or 365 days, the amount remaining will be about:

$f(365)=510e^{365\ln(.5)/38}\approx 0.6548$

5 0

2 years ago

Find the area of the equilateral triangle whose sides are 4 yd.

suter [353]

Answer:

The first one. 4 times square root of 3.

Step-by-step explanation:

The side of the equilateral triangle that represents the height of the triangle will have a length of because it will be opposite the 60o angle. To calculate the area of the triangle, multiply the base (one side of the equilateral triangle) and the height (the perpendicular bisector) and divide by two.

4 0

2 years ago

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