Answer:
X (millions) 1 5 10
P(x) 0,1 0,6 0,3
Step-by-step explanation:
In this case, the probability mass function of X is the function that relates the money produced for the product with the probability of obtain this profit of the product.
The mass function will be:
X (millions) 1 5 10
P(x) 0,1 0,6 0,3
This is a probability mass function because the sum of the probabilities of each value is 1. 0.1+0.6+0.3=1
So hmm notice the picture below
a)
the center of the circle is the midpoint of those two folks
![\bf \textit{middle point of 2 points }\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ -10}}\quad ,&{{ -2}})\quad % (c,d) &({{ 4}}\quad ,&{{ 6}}) \end{array}\qquad % coordinates of midpoint \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right) \\\\\\ \left(\cfrac{4-10}{2}\quad ,\quad \cfrac{6-2}{2} \right)\impliedby \textit{center of the circle}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bmiddle%20point%20of%202%20points%20%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Cbegin%7Barray%7D%7Blllll%7D%0A%26x_1%26y_1%26x_2%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0A%26%28%7B%7B%20-10%7D%7D%5Cquad%20%2C%26%7B%7B%20-2%7D%7D%29%5Cquad%20%0A%25%20%20%28c%2Cd%29%0A%26%28%7B%7B%204%7D%7D%5Cquad%20%2C%26%7B%7B%206%7D%7D%29%0A%5Cend%7Barray%7D%5Cqquad%0A%25%20%20%20coordinates%20of%20midpoint%20%0A%5Cleft%28%5Ccfrac%7B%7B%7B%20x_2%7D%7D%20%2B%20%7B%7B%20x_1%7D%7D%7D%7B2%7D%5Cquad%20%2C%5Cquad%20%5Ccfrac%7B%7B%7B%20y_2%7D%7D%20%2B%20%7B%7B%20y_1%7D%7D%7D%7B2%7D%20%5Cright%29%0A%5C%5C%5C%5C%5C%5C%0A%5Cleft%28%5Ccfrac%7B4-10%7D%7B2%7D%5Cquad%20%2C%5Cquad%20%5Ccfrac%7B6-2%7D%7B2%7D%20%5Cright%29%5Cimpliedby%20%5Ctextit%7Bcenter%20of%20the%20circle%7D)
b)
the diameter is the distance between P and Q, or the length of that segment, and the radius is half the diameter
![\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ -10}}\quad ,&{{ -2}})\quad % (c,d) &({{ 4}}\quad ,&{{ 6}}) \end{array}\quad % distance value d = \sqrt{({{ 4}}-{{ (-10)}})^2 + ({{ 6}}-{{ (-2)}})^2} \\\\\\ d=\cfrac{\sqrt{(4+10)^2+(6+2)^2}}{2}\impliedby \textit{radius of the circle}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Cbegin%7Barray%7D%7Blllll%7D%0A%26x_1%26y_1%26x_2%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0A%26%28%7B%7B%20-10%7D%7D%5Cquad%20%2C%26%7B%7B%20-2%7D%7D%29%5Cquad%20%0A%25%20%20%28c%2Cd%29%0A%26%28%7B%7B%204%7D%7D%5Cquad%20%2C%26%7B%7B%206%7D%7D%29%0A%5Cend%7Barray%7D%5Cquad%20%0A%25%20%20distance%20value%0Ad%20%3D%20%5Csqrt%7B%28%7B%7B%204%7D%7D-%7B%7B%20%28-10%29%7D%7D%29%5E2%20%2B%20%28%7B%7B%206%7D%7D-%7B%7B%20%28-2%29%7D%7D%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Ad%3D%5Ccfrac%7B%5Csqrt%7B%284%2B10%29%5E2%2B%286%2B2%29%5E2%7D%7D%7B2%7D%5Cimpliedby%20%5Ctextit%7Bradius%20of%20the%20circle%7D)
c)
so, from a), you found the h,k coordinates for the center, from b) you've got the radius
so, just plug them in here then
Answer:
A.Is Invisible
B.Is Iniviatable
C.Is Blank
D.Is Nothing
Step-by-step explanation:
Dont Thanks me if theres are nothing
324, 361, 400
18^2=324
19^2=361
20^2=400
False, ex: 18/2 = 9
false, ex: 18/2 = 9