Use the image above to identify and explain the relationship between the segments and circles A and B. In your explanation, be s
ure to include specific vocabulary and definitions for the relationships.
ER
ER
2 answers:
Answer with explanation:
Relationship between Circle A and Circle B
Size of Circle A is Bigger than Size of Circle B.
So,⇒ Radius of Circle A > Radius of circle B
⇒Relationship between Segments
1.
Let Segment QT and ER intersect at point M.
Also, length of Tangents from external point to a circle are equal.
QM = ME--------(1)
MT=MR--------(2)
Adding (1) and (2)
QM + MT= MR +ME
→Q T=ER
2.
Length of Tangents from external point to a circle are equal.Using this property we can write following segments are equal.
UP=U Q
Z C=ZR
V C=VS
NR=NS
KC=K T
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Answer:
0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
Find the probability that the diameter of a selected bearing is greater than 85 millimeters.
This is 1 subtracted by the pvalue of Z when X = 85. Then
has a pvalue of 0.7486.
1 - 0.7486 = 0.2514
0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.