In the problem, how do you get 6,300,000 using the digits 1-7 to create a
seven-digit number that can be rounded to 6,300,000.
We can use the numbers according to the rule of rounding values, 0-4 and
5-9.
Hence the numbers are:
1. 6, 290,000 = 6, 300, 000
2. 6, 310, 000 = 6, 300, 000
Therefore the numbers concerned in the given value is in the place order of
ten thousand which will determine the hundred thousands’ value.
Answer:
d
Step-by-step explanation:
becuse the first one would be 4x and the other ones 2x
<span>(2p + q) ( –3q – 6p + 1)
= -6pq - 12p^2 + 2p - 3q^2 - 6pq + q
= -12p^2 -12pq +2p -3q^2 + q
so answer is b. </span> -12p^2 -12pq +2p -3q^2 + q
