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3 years ago

Help me please I need help?

Mathematics

2 answers:

GarryVolchara [31]3 years ago

8 0

Your answer will be ether 10 or 12 I think 12

liubo4ka [24]3 years ago

4 0

I think it is D

I am not sure but this is what I think it is

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nirvana33 [79]

Answer:

$= 15.6 \times 18 \\ = 280.8 \: {in}^{2} \\ = > \: six \: sides \\ = 280.8 \times 6 \\ = 1684.8 \: {in}^{2}$

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2 years ago

20 POINTS!!!

notka56 [123]

$\dfrac{2}{\sqrt3\cos x+\sin x}=\sec\left(\dfrac{\pi}{6}-x\right)\\\\\dfrac{2}{\sqrt3\cos x+\sin x}=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}\ \ \ \ \ (*)\\----------------\\\\\cos\left(\dfrac{\pi}{6}-x\right)\ \ \ \ |\text{use}\ \cos(x-y)=\cos x\cos y+\sin x\sin y\\\\=\cos\dfrac{\pi}{6}\cos x+\sin\dfrac{\pi}{6}\sin x=\dfrac{\sqrt3}{2}\cos x+\dfrac{1}{2}\sin x=\dfrac{\sqrt3\cos x+\sin x}{2}\\------------------------------$

$(*)\\R_s=\sec\left(\dfrac{\pi}{6}-x\right)=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}=\dfrac{1}{\dfrac{\sqrt3\cos x+\sin x}{2}}\\\\=\dfrac{2}{\sqrt3\cos x+\sin x}=L_s$

6 0

2 years ago

Read 2 more answers

Question 1

wariber [46]

Answer:

Step-by-step explanation:

n 1

f( – 2)

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How do we work this? I cannot figure out the path to solve. Th 4x2 + 3x + 1, evaluate f( - 2)

f( – 2)

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How do we work this? I cannot figure out the path to solve. Th

5 0

3 years ago

Square root of 6 times [(square root of 30)-2]

Oksanka [162]

The distributive property is...

a(b + c) = ab + ac

a(b - c) = ab - ac

So...

root6 (root30 - 2)

= root6 x root30 - root6 x 2

= root180 - 2root6

= 6root5 - 2root6

6root5 means 6 x root5

2root6 means 2 x root6

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3 years ago

Evaluate. 8m - 4 + 3n n = 5 and m = 2

umka2103 [35]

8m - 4 + 3n
= 8*2 - 4 + 3*5
= 16 - 4 + 15
= 27 ← answer

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3 years ago

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