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Anon25 [30]
3 years ago
5

If you multiply by 3 negatives does it equal a negative?

Mathematics
1 answer:
qwelly [4]3 years ago
6 0

Yes it does because when u multiply 2 negative you get a positive but since your adding another negative it goes back to a negative

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A figure has vertices at the points (6,5), (6,-4), (-4,-4) and (-4,5). What is the area of the figure
Oxana [17]

Answer:

  90 units²

Step-by-step explanation:

The rectangular figure is 10 units wide (from -4 to +6) and 9 units high (from -4 to +5), so its area is 10·9 = 90 square units.

7 0
3 years ago
Triangle TRI has a base of m centimeters and a height of n centimeters. Rectangle RECT has a length of n centimeters and a width
hram777 [196]
The area of the triangle is 
a=( m x n) /2  in cm² , implies   2xa = m xn
the area of the rectanglle
A= n x m  in cm²
but we know  <span>  2xa = m xn = A,  </span>
that means  the surface of the rectangle is 2 times of the area of the triangle
7 0
3 years ago
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What property is 10(5+9x) and 10(9x+5)
tatuchka [14]

Answer:

Associative property: The addition or multiplication of a several numbers is the same regardless of how the numbers are grouped. The associative property will always involve 3 or more numbers. The parenthesis groups the terms that are considered one unit.

8 0
3 years ago
Write an equation of the line below.
iVinArrow [24]

(0,-2)

(5,-7)

hope it helps u

5 0
2 years ago
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Find the equation of the line perpendicular to y =<br> 3x + 6 and containing the point (-9,-5).
neonofarm [45]

The equation of the line perpendicular to y =  3x + 6 and containing the point (-9,-5) is y = \frac{-1}{3}x - 8

<em><u>Solution:</u></em>

Given that line perpendicular to y =  3x + 6 and containing the point (-9, -5)

We have to find the equation of line

<em><u>The slope intercept form is given as:</u></em>

y = mx + c  ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

<em><u>Let us first find the slope of line</u></em>

The given equation of line is y = 3x + 6

On comparing the given equation of line y = 3x + 6 with eqn 1, we get,

m = 3

Thus the slope of given equation of line is 3

We know that <em>product of slopes of given line and slope of line perpendicular to given line is equal to -1</em>

Slope of given line \times slope of line perpendicular to given line = -1

3 \times \text{ slope of line perpendicular to given line }= -1

\text{ slope of line perpendicular to given line } = \frac{-1}{3}

Let us now find the equation of line with slope m = \frac{-1}{3} and containing the point (-9, -5)

Substitute m = \frac{-1}{3} and (x, y) = (-9, -5) in eqn 1

-5 = \frac{-1}{3}(-9) + c\\\\-5 = 3 + c\\\\c = -8

<em><u>Thus the required equation of line is:</u></em>

Substitute m = \frac{-1}{3} and c = -8 in eqn 1

y = \frac{-1}{3}x - 8

Thus the required equation of line perpendicular to given line is found

6 0
3 years ago
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