HELPP MEEE BC I DIDNT POST MY PICCC

Imagine if you're in a room filling up with water. there are no windows/doors and you can't break anything, how do you get out?

marysya [2.9K]

Answer:

this message for guys... Guys who's interesting in fking girls? because I want someone 2 fk me from my psy soo hot

4 0

4 years ago

The graphed line can be expressed by which equation?

statuscvo [17]

What equation? Can’t really help you if there is no equation there

4 0

3 years ago

Read 2 more answers

Find the product. (5ab3b) (2ab) PLEASE HELP!!! ASAP!!!

Lostsunrise [7]

Answer:

10a²b²6ab²

Step-by-step explanation:

Distribute the 2ab the other values

4 0

3 years ago

Write a power represented with a positive base and a positive exponent whose value is less then the base

sasho [114]

Answer:

The question is open ended as i suppose since there are infinitely many possibilities. one possible form of the solution can be $5^{2}$

Step-by-step explanation:

The base in this case is 5 while the exponent is simply the power to which the base is raised in which case it would be 2. Both values are positive and the exponent is less than the base.

6 0

4 years ago

Felix and Oscar are standing on a tower that is 112 feet high. Felix drops his penny while Oscar throws his penny down and it hi

creativ13 [48]

Answer:

It will take 2.64 s for Felix's penny to hit the ground.

Initial velocity of Oscar's penny is 7.27 m/s or 23.85 ft/s

Step-by-step explanation:

Given:

Height of the tower is, $h=112\ ft$

Felix drops the penny while Oscar throws his penny.

Time taken by Oscar's penny to reach ground is, $t_o=2\ s$

Now, as Oscar throws his penny, there will be some initial velocity of his penny. Let the initial velocity of his penny be $u_o$ .

As the penny is falling vertically, acceleration of the penny is due to gravity and is equal to -9.8 m/s².

Now, displacement of the penny is equal to the height of the tower = -112 ft = -34.14 m (1 ft = 0.3048 m)

Using equation of motion,

$y=u_ot+\frac{1}{2}at_o^2\\\\-34.14=2u_o-\frac{1}{2}\times9.8\times 2^2\\\\-34.14=2u_o-19.6\\\\2u_o=-34.14+19.6\\\\2u_o=-14.54\\\\u_o=\frac{-14.54}{2}=-7.27\ m/s$

Now, 1 m/s = 3.28 ft/s

So, 7.27 m/s = $7.27\times 3.28 = 23.85\ ft/s$

Therefore, the initial velocity of Oscar's penny is 7.27 m/s or 23.85 ft/s in the downward direction.

Now, Felix drops the penny. So, initial velocity of Felix's penny is 0 m/s.

Displacement of the penny is same and equal to -112 ft = -34.14 m

Using the same equation of motion,

$y=ut+\frac{1}{2}at^2\\\\-34.14=0-\frac{1}{2}\times9.8\times t^2\\\\-34.14=-4.9t^2\\\\t^2=\frac{-34.14}{-4.9}\\\\t=\sqrt{\frac{-34.14}{-4.9}}\\\\ t=2.64\ s$

Therefore, time taken by Felix's penny to reach ground is 2.64 s.

8 0

4 years ago