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3 years ago

Write each ratio statement as a fraction and reduce the two lowest terms 14:42

Mathematics

2 answers:

Harrizon [31]3 years ago

8 0

123344545677 yes it trew

LuckyWell [14K]3 years ago

7 0

14:42 = 14/42 = 1/3
This ones right sorry answered wrong question lol

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A 15-minute TV program consists of one commercial of 1

Margarita [4]

Answer:

6 7/8 minutes

Step-by-step explanation:

Say the entertainment segments are each x minutes long. Then, we have the equation:

x + x + 1 1/4 = 15

2x + 1 1/4 = 15

2x = 15 - 1 1/4

We need a common denominator. 1 1/4 = 5/4 and 15 = 60/4, so we now have:

60/4 - 5/4 = 55/4. Then: 2x = 55/4

Divide by 2 from both sides:

(55/4) / 2 = 55/8 = 6 7/8

Thus, each entertainment segment is 6 7/8 minutes long.

Hope this helps!

7 0

3 years ago

Read 2 more answers

- What is the equation of a cirde with a center

wlad13 [49]

Answer:

Step-by-step explanation:

The equationof a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have center = (4, -1) → h = 4, k = -1, and r = 9.

Substitute:

$(x-4)^2+(y-(-1))^2=9^2\\\\\huge\boxed{(x-4)^2+(y+1)^2=81}$

6 0

2 years ago

Read 2 more answers

It is generally claimed that the average body temperature for healthy human adults is 98.6°F. To test this claim a simple random

Rzqust [24]

Answer:

Explained below.

Step-by-step explanation:

The information provided is as follows:

$\mu=98.6^{o}F\\\bar x=98.1^{o}F\\s=0.9^{o}F\\n=9$

(1)

A single mean test is to be performed in this case.

As the population standard deviation is not provided, a one-sample t-test will be used.

The correct option is b.

(2)

The null hypothesis is:

H₀: The average temperature in the population is 98.6°F, i.e. μ = 98.6°F.

The correct option is b.

(3)

The alternative hypothesis is:

Hₐ: The average temperature in the population is less than 98.6°F, i.e. μ < 98.6°F.

The correct option is c.

(4)

The standard deviation of the sample mean is as follows:

$SD_{\bar x}=\frac{s}{\sqrt{n}}=\frac{0.9}{\sqrt{9}}=0.3^{o}F$

Thus, the value of SD is 0.3°F.

(5)

Compute the value of test statistic as follows:

$t=\frac{\bar x-\mu}{SD_{\bar x}}$

$=\frac{98.1-98.6}{0.3}\\\\=-1.666666667\\\\\approx -1.67$

Thus, the value of test statistic is -1.67.

(6)

The degrees of freedom of the test are:

df = n - 1

= 9 - 1

= 8

Thus, the degrees of freedom of the test is 8.

8 0

3 years ago

*Asymptotes* g(x) =2x+1/x-3 Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .