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2 years ago

PLEASE HELP ASAP CONGRUENCE IN RIGHT TRIANGLES

Mathematics

1 answer:

Pani-rosa [81]2 years ago

4 0

Answer:

We know that the angles of a triangle always add up to 180 degrees, and we also know that this triangle is congruent because it has the two dashes on the side of the triangle. We also know that x is 90 degrees but this is not drawn to scale but we can just assume it is 90 degrees.

We can tackle the triangle on the right first subtracting 47 and 90 from 180 which will give us the angle y as angle DAC is congruent to angle BAC.

180-47-90=43.

We also know that angle x is 90 degrees already or at least we assume so but to further prove our point we know that angle BCA is congruent to angle CBA which makes angle CBA 47 degrees, so subtracting 43 and 47 from 180 we have 90 degrees.

Therefore y is 43 degrees and x is 90 degrees.

it's kinda confusing ngl

*assuming that x is a right angle

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1/6

Step-by-step explanation:

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2 years ago

Find the surface area of the following figure.

fgiga [73]

Answer:

$\boxed{\textsf{\pink{ Hence the TSA of the cuboid is $\sf 32x^2$}}}.$

Step-by-step explanation:

A 3D figure is given to us and we need to find the Total Surface area of the 3D figure . So ,

From the cuboid we can see that there are 5 squares in one row on the front face . And there are two rows. So the number of squares on the front face will be 5*2 = 10 .

We know the area of square as ,

$\qquad\boxed{\sf Area_{(square)}= side^2}$

Hence the area of 10 squares will be 10x² , where x is the side length of each square. Similarly there are 10 squares at the back . Hence their area will be 10x² .

Also there are in total 12 squares sideways 6 on each sides . So their surface area will be 12x² . Hence the total surface area in terms of side of square will be ,

$\sf\implies TSA_{(cuboid)}= 10x^2+10x^2+12x^2\\\\\sf\implies\boxed{\sf TSA_{(cuboid)}= 32x^2}$

Now let's find out the TSA in terms of side . So here the lenght of the cuboid is equal to the sum of one of the sides of 5 squares .

$\sf\implies 5x = l \\\\\sf\implies x = \dfrac{l}{5} \\\\\qquad\qquad\underline\red{ \sf Similarly \ breadth }\\\\\sf\implies b = 3x \\\\\sf\implies x = \dfrac{ b}{3}$

$\rule{200}2$

Hence the TSA of cuboid in terms of lenght and breadth is :-

$\sf\implies TSA_{(cuboid)}= 10x^2+10x^2+12x^2\\\\\sf\implies TSA_{(cuboid)}= 20\bigg(\dfrac{l}{5}\bigg)^2+12\bigg(\dfrac{b}{3}\bigg) \\\\\sf\implies TSA_{(cuboid)}= 20\times\dfrac{l^2}{25}+12\times \dfrac{b^2}{9}\\\\\sf\implies \boxed{\red{\sf TSA_{(cuboid)}= \dfrac{4}{5}l^2 +\dfrac{4}{3}b^2 }}$

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2 years ago

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3 years ago

Read 2 more answers

Help please? I need it lol

ddd [48]

Answer:

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