Answer:
Im not sure
Step-by-step explanation:
Sorry
Answer:
yes
Step-by-step explanation:
Hi there!
We want to see if 9, 40, and 41 can be the sides of a triangle that can exist
We can use triangle inequalities to figure that out
For triangle inequalities, if the lengths of the sides are a, b, and c, then a+b>c, b+c>a, and c+a>b, then the lengths can make a triangle
Let's say that a=9, b=40, and c=41
Now substitute these values into the inequalities:
a+b>c
9+40>41
49>41
This is a true statement.
b+c>a
40+41>9
81>9
This is also a true statement.
41+9>40
50>40
This is a true statement as well.
Since all three of the inequalities ended up being true (all three NEED to be true in order for the given lengths to make a triangle), then we can confirm that 9, 40, and 41 can make a triangle
Hope this helps!
See more on this topic here: brainly.com/question/17357347
first off let's notice that hmmm the vertex is above the point (3,-3), so if we "assume" is a vertical parabola, then it'd be opening downwards.... anyhow that said, let's plug in those values.
![\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Bvertical%20parabola%20vertex%20form%7D%20%5C%5C%5C%5C%20y%3Da%28x-%20h%29%5E2%2B%20k%5Cqquad%20%5Cbegin%7Bcases%7D%20%5Cstackrel%7Bvertex%7D%7B%28h%2Ck%29%7D%5C%5C%5C%5C%20%5Cstackrel%7B%22a%22~is~negative%7D%7Bop%20ens~%5Ccap%7D%5Cqquad%20%5Cstackrel%7B%22a%22~is~positive%7D%7Bop%20ens~%5Ccup%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
![\bf vertex~~(\stackrel{h}{2}~~,~~\stackrel{k}{1})\qquad \implies \qquad y = a(x-2)^2+1 \\\\\\ \stackrel{\textit{we also know that }}{(3~~,~~-3)} \begin{cases} x = 3\\ y = -3 \end{cases}\qquad \implies -3=a(3-2)^2+1 \\\\\\ -3=a(1)^2+1\implies -3=a+1\implies -4=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y = -4(x-2)^2+1~\hfill](https://tex.z-dn.net/?f=%5Cbf%20vertex~~%28%5Cstackrel%7Bh%7D%7B2%7D~~%2C~~%5Cstackrel%7Bk%7D%7B1%7D%29%5Cqquad%20%5Cimplies%20%5Cqquad%20y%20%3D%20a%28x-2%29%5E2%2B1%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bwe%20also%20know%20that%20%7D%7D%7B%283~~%2C~~-3%29%7D%20%5Cbegin%7Bcases%7D%20x%20%3D%203%5C%5C%20y%20%3D%20-3%20%5Cend%7Bcases%7D%5Cqquad%20%5Cimplies%20-3%3Da%283-2%29%5E2%2B1%20%5C%5C%5C%5C%5C%5C%20-3%3Da%281%29%5E2%2B1%5Cimplies%20-3%3Da%2B1%5Cimplies%20-4%3Da%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20y%20%3D%20-4%28x-2%29%5E2%2B1~%5Chfill)
Answer:
Hey! I see you need some help, I gotchu.so heres what i got,
Medication A: 32 would be the main answer
Step-by-step explanation:
Week 1- even medication from A and medication B
Week2- Medication A: 80 milligrams Medication B: 48 milligrams
week 3- Medication A:? Medication B: 6
They seem to be reducing it by 42, so 48-42=6 (medication B)
So therefore, 80-42=32. would be for medication A
