Question

The equation of line q is 5y - 4x = 10. Write an equation of the line that is perpendicular to q and passes through the point (-15, 8).

Answer 1

5y=4x+10  /:5
y=4/5 x+2
y=mx+k
m₁*m₂=-1
4/5 *m=-1
m=-5/4
y=-5/4 x+k
-5/4*(-15)+k=8
75/4 + k=8
k=32/4 - 75/4
k=-53/4=-13.25
y=-5/4 x - 53/4