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Juli2301 [7.4K]
3 years ago
6

Write the slope-intercept form of the equation of each line.

Mathematics
1 answer:
gregori [183]3 years ago
5 0

Greetings!

Answer:

2y = x - 6

Step-by-step explanation:

First, we must find the slope of the current equation.

This is the number in front of the x.

Seeing as this is -2x, the slope of this line is -2

When finding the slope of a line perpendicular, you need to find the \frac{-1}{slope}

So, in this case it is:

\frac{-1}{-2}

The negatives cancel out which leave \frac{1}{2}

So the gradient is \frac{1}{2}


Now, to find the equation of a line, you need to use:

y - y1 = m(x - x1)

Where ya and x1 are the values in the coordinates (2 , -2)

So y1  = -2, x1 = 2, and m is a half. Plug these values in:

y - - 2 = \frac{1}{2}(x - 2)

We need to get rid of the half so we multiply the whole equation by 2:

2y - - 4 = (x - 2)

The minus and the negative turn into a positive:

2y + 4 = x - 2

And now simply move the +4 over to the other side, making it a negative:

2y =  -2 - 4 + x

Simplify:

2y = x - 6

<h3>So the equation of the line is 2y = x - 6</h3>
<h2>Hope this helps!</h2>
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Answer:

82.79MPa

Step-by-step explanation:

Minimum yield strength for AISI 1040 cold drawn steel as obtained from literature, Sᵧ = 490 MPa

Given, outer radius, r₀ = 25mm = 0.025m, thickness = 6mm = 0.006m, internal radius, rᵢ = 19mm = 0.019m,

Largest allowable stress = 0.8(-490) = -392 MPa (minus sign because of compressive nature of the stress)

The tangential stress, σₜ = - ((r₀²p₀)/(r₀² - rᵢ²))(1 + (rᵢ²/r²))

But the maximum tangential stress will occur on the internal diameter of the tube, where r = rᵢ

σₜₘₐₓ = -2(r₀²p₀)/(r₀² - rᵢ²)

p₀ = - σₜₘₐₓ(r₀² - rᵢ²)/2(r₀²) = -392(0.025² - 0.019²)/2(0.025²) = 82.79 MPa.

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