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3 years ago

3 (4x - 2) - 30 = -6 (6 - 2x) - 20

Mathematics

1 answer:

irga5000 [103]3 years ago

6 0

Answer:

Step-by-step explanation:

3(4x-2)-30=-6(6-2x)-20

12x-6-30=-36+12x-20

12x-36=12x-56

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A scientist used 2 gallons of liquid for every 3 hours he works. He uses __ of a gallon each hour he works.

tiny-mole [99]

He uses 2/3 of a gallon each hour he works.

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2 years ago

Can someone please answer. There is only one problem. There is a picture. Thank you!

KATRIN_1 [288]

5Red + 6Blue + 4 Black

Total = 5 + 6 = 4 = 15

Probality of Blue, Blue.

P(Blue) = 6/15 = 2/5

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2 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%28-81%29x%5E%7B2%7D%20%7D" id="TexFormula1" title="\sqrt{(-81)x^{2} }" alt="\sqrt{(

SSSSS [86.1K]

Answer:

We conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

Step-by-step explanation:

Given the radical expression

$\sqrt{\left(-81\right)x^2}$

simplifying the expression

$\sqrt{\left(-81\right)x^2}$

Remove parentheses: (-a) = -a

$\sqrt{\left(-81\right)x^2}=\sqrt{-81x^2}$

Apply radical rule: $\sqrt{-a}=\sqrt{-1}\sqrt{a},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=\sqrt{-1}\sqrt{81x^2}$

Apply imaginary number rule: $\sqrt{-1}=i$

$=i\sqrt{81x^2}$

Apply radical rule: $\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

$=\sqrt{81}i\sqrt{x^2}$

$=9i\sqrt{x^2}$

Apply radical rule: $\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$=9ix$

Therefore, we conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

7 0

2 years ago

What is the value of the power a if 5 to the power of a is equal to 1/125

padilas [110]

First of all, you should know/notice that

$125=5^3$

You should also know how negative exponents work:

$a^{-m}=\dfrac{1}{a^m}$

So, if you wanted

$5^x=125$

the answer would be x=3, but since you want 125 to be at the denominator, the answer is x=-3:

$5^{-3}=\dfrac{1}{5^3}=\dfrac{1}{125}$

7 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

aev [14]

Answer: (B) -625

<u>Step-by-step explanation:</u>

Given the sequence {-500, -100, -20, -4, -0.8, ... }, we know that that the first term (a) is -500 and the ratio (r) is $\dfrac{-100}{-500}=\dfrac{1}{5}$

Input those values into the Sum formula:

$S_n=\dfrac{a(1-r^n)}{1-r}\\\\S_8=\dfrac{-500\bigg(1-\dfrac{1}{5}^n\bigg)}{1-\dfrac{1}{5}}\\\\.\quad=\dfrac{-500\bigg(1-\dfrac{1}{390,625}\bigg)}{\dfrac{4}{5}}\\\\.\quad=\dfrac{-500\bigg(\dfrac{390,624}{390,625}\bigg)}{\dfrac{4}{5}}\\\\.\quad=\dfrac{5(-500)(390,624)}{4(390,625)}\\\\.\quad=-624.998\\\\.\quad=-625\quad \text{(rounded to 2 decimal places)}$

4 0

3 years ago