1/6
explanation:
1 x 1 = 1
2 x 3 = 6
1/6
Hope it helps!
The answer to the mathematics question presented above is 'True'. It is correct to say that in (r theta), the value of r can be negative. A negative radius can be used when it comes to graphing a "polar'' function. Thus, the answer to the question is 'true'.
Answer:
Step-by-step explanation:
y = -x + 1......same as y = -1x + 1.....in y = mx + b form, ur slope is in the m position....so the slope of this line is -1.
a parallel line will have the same slope.
(-1,3)...x = -1 and y = 3
slope(m) = -1
y = mx + b.....we have x,y, and m....now we need to find y int (b)
3 = -1(-1) + b
3 = 1 + b
3 - 1 = b
2 = b
so ur parallel equation is : y = -1x + 2...or just y = -x + 2
<span>3x^2y^2 − 2xy^2 − 8y^2 =
y^2 (3x^2 - 2x - 8) =
factoring with leading coefficient:
for ax2+bx+c find two numbers n,m, that m*n = a*c and m+n = b
</span><span><span>
3x^2 - 2x - 8
a=3, b=-2, c=-8
</span>a*c = 3*(-8) = -24
-24=(-6)*4 and -6+4=-2, so m=-6 and n=4
replace bx with mx + nx and factor by grouping
</span><span>
3x^2 - 2x - 8 = </span>3x^2 -6x + 4x -8 = 3x(x-2) + 4(x-2) = (3x+4)(x-2)
answer:
<span>3x^2y^2 − 2xy^2 − 8y^2 = y^2(3x+4)(x-2)</span>
