The vertex of a parabola is the point where the parabola crosses its axis of symmetry. Therefore, the coordinates of the vertex is (2,4).
There are 6 (five sixteenths) in 1 and (seven eighths)
Answer:
BRUH I DONT KNOW
Step-by-s
4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) DO ALL OF THAT TO FIND THE ANSWER