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ludmilkaskok [199]
3 years ago
9

#2

Mathematics
1 answer:
love history [14]3 years ago
6 0
21.25 divided by 5 equals 4.25
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I’m having a hard time understanding substitution. Please help!
Vikentia [17]

b_1=\frac{2A}{h}-b_2

Step-by-step explanation:

Given expression is;

A=\frac{h(b_1+b_2)}{2}

Solving for b_1

Multiplying both sides by 2

2*A=\frac{h(b_1+b_2)}{2}*2\\2A=h(b_1+b_2)

Dividing both sides by h

\frac{2A}{h}=\frac{h(b_1+b_2)}{h}\\\frac{2A}{h}=b_1+b_2

Subtracting b_2 from both sides

\frac{2A}{h}-b_2=b_1+b_2-b_2\\\frac{2A}{h}-b_2=b_1\\b_1=\frac{2A}{h}-b_2

b_1=\frac{2A}{h}-b_2

Keywords: division, subtraction

Learn more about subtraction at:

  • brainly.com/question/11145277
  • brainly.com/question/11150876

#LearnwithBrainly

3 0
3 years ago
2. In what ratio does the point (5, 4) divide the given line joining the points (2,1) and (7,6)​
Darya [45]

Answer:

3/2

Step-by-step explanation:

Let it be

C (5;4) , A (2;1) ; B(7;6)

Suppose that C divide the line AB in ratio m/n from point A (AC is m, CB is n)

Use the formula xc=(m*xb+n*xa)/ (m+n)

5=(m*7+2n)/(m+n)

5m+5n= 7m+2n

2m=3n

m/n=3/2

5 0
2 years ago
Please help me!!! I will try to mark brainliest if the answer is correct!
netineya [11]

Answer:

I think the first is answer bcz 35+55=90 ..... 180-90=90

5 0
3 years ago
Please help me on my homework
Irina-Kira [14]

the correct answer is $948

6 0
2 years ago
A population of 30 deer are introduced into a wildlife sanctuary. It is estimated that the sanctuary can sustain 600 deer. The p
Ksju [112]

Complete question :

A population of 30 deer are introduced into a wildlife sanctuary. It is estimated that the sanctuary can sustain 600 deer. The population would grow by 30 percent per year

how many after one year

how many after two years

Answer:

39 deers

51 deers

Step-by-step explanation:

The question can be expressed using the compounding rate formula:

A = P(1+r)^t

A = final population ; P = initial population ; rate, r = 30% = 0.3 ; t = time

After 1 year, t = 1

A = 30(1 + 0.3)^1

A = 30(1.3)^1

A = 39 deers

B.)

After 1 year, t = 2

A = 30(1 + 0.3)^2

A = 30(1.3)^2

A = 50.7

A = 51 deers approximately

4 0
3 years ago
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