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AlekseyPX
3 years ago
10

What is 2,722 round to the nearest thousand

Mathematics
2 answers:
kolbaska11 [484]3 years ago
6 0
The answer is 3,000. That is because the number 7 in the hundreds place is over 5. And when a number is 5 and over, you round up one number. But if that number was to be 4 or lower, that number stays the same. After that number has been rounded, all the numbers before that digit becomes a 0.
Ray Of Light [21]3 years ago
3 0
2,000.....................
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Each student on the trip to cooperstown paid the same amount .the tottal amount collected was $589.pilar paid for her ticket usi
professor190 [17]

Answer:

$231.67

Step-by-step explanation:

how you need to divide 589 to 3 and than you get 231.67

5 0
3 years ago
2. Check the boxes for the following sets that are closed under the given
son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Addition

   c) AdditionSum

   d) in this case we have two possibilities

       * If we move to the right the addition

       * If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

        -3 -1 = -4

        -4 -1 = -5

        -7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) 0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}  ...

In this case we can see more clearly the sequence when writing in this way

      0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}

each term is found by adding 1 to the current term,

      \sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}

Therefore the mathematical operation is the addition

c)   ... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...

      The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

  • To move to the right add 1

           -\frac{-10}{2} + 1 = \frac{-10}{2}  -   \frac{2}{2}  = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}

  • To move left subtract 1

         \frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}

         

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Sum

   c) Sum

   d) This case we have two possibilities

  •  If we move to the right the sum
  •  If we move to the left we subtract

Learn more here: brainly.com/question/4626313

5 0
3 years ago
Multiplying Binomials: (−2h+9)(9h−2) = ?
oee [108]
(−2h+9)(9h−2)

-18h^2 + 4h + 81h - 18

Answer: -18h^2 + 85h - 18
5 0
3 years ago
Using 6 as a denominator, what fraction completes the following
mixas84 [53]

Answer:

B

Step-by-step explanation:

We can start by converting 1 into 6/6 and 1/3 into 2/6. This makes subtraction much easier, and by subtracting the numerators, (6/6 - 2/6) you should get 4/6.

5 0
3 years ago
12.09 - 03.37<br> What is 12.09 - 03.37
Bingel [31]
Answer: 8.72
hoped this helped
3 0
3 years ago
Read 2 more answers
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