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bagirrra123 [75]
3 years ago
12

An observer on the ground is x meters from the base of the launch pad of a rocket, which is at the same level as the observer. A

few seconds after the rocket takes off vertically, the observer sees its tip at an angle of q° from the horizontal. How far above the ground is the tip of the rocket at that instant? Assume that the ground is level.. a) x/ tan q. b) x/sin q. cx tan q. d) x cos q.
Mathematics
2 answers:
Firlakuza [10]3 years ago
5 0
This can be solved using trigonometric functions. The distance x serves as one leg of a triangle, and makes an angle q with the hypotenuse. The distance from the tip of the rocket to the ground make up the other leg of the triangle. So solving this:

tan q = y / x

Where: y = distance from the tip of the rocket to the ground

Therefore, y = x tan q

Among the choices, the correct answer is C.
SVETLANKA909090 [29]3 years ago
3 0

Answer:C

Step-by-step explanation:

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Which of the following is the radical expression of?
SSSSS [86.1K]

Answer:

The third answer

Step-by-step explanation:

Remember power over root and the 2 would not be under the root.

5 0
3 years ago
The cross-sectional areas of a right triangular prism and a right cylinder are congruent. The right triangular prism has a heigh
Lina20 [59]

Answer:

B.)The volume of the triangular prism is not equal to the volume of the cylinder.

Step-by-step explanation:

Let A be the cross-sectional area of both congruent right triangular prism and right cylinder.

Since the prism has height 2 units, its volume V₁ = 2A.

Since the cylinder has height 6 units, its volume is V₂ = 6A

Dividing V₁/V₂ = 2A/6A =1/3

V₁ = V₂/3.

The volume of the prism is one-third the volume of the cylinder.

So, since the volume of the prism is neither double nor half of the volume of the cylinder nor is it equal to the volume of the cylinder, B is the correct answer.

So, the volume of the triangular prism is not equal to the volume of the cylinder.

5 0
3 years ago
Half an hour after leaving her house Beverly was 20 miles from home. At this point she merged onto the highway and was traveling
N76 [4]

Answer:

1. 45.71 miles

2. 10 miles

3. 89.43 miles

4. 0.79 hr

5. 0.025 hr

Step-by-step explanation:

speed = distance/time

After 4 hrs Beverly was 200 miles from home , however she had spent 0.5hr travelling for 20 miles prior to getting to the highway.

Therefore;

Constant speed before Highway = 20/0.5 = 40 miles/hr

Constant speed at Highway = \frac{(200-20)}{(4-0.5)} = 51.43 miles/hr

1. in 1 hr beverly will have travelled;

⇒ (20 miles in 0.5 hr ) + (0.5 hr  at speed 51.43 miles/hr)

⇒ 20 + (0.5 x 51.43) = 45.71 miles

2. In 0.25 hr beverly had not reached the highway

⇒ distance = speed x time

⇒ distance = 40 x 0.25 = 10 miles

3. in 1.85 hrs beverly will have travvelld;

⇒ (20 miles in 0.5 hr ) + (1.35 hr at speed 51.43 miles/hr)

⇒ 20 + 69.43 = 89.43 miles

4. Time taken to get to 35 miles

⇒ (20 miles in 0.5 hr ) + (15 miles  at speed 51.43 miles/hr)

⇒ 0.5hr + (15/51.43) hr = 0.79 hr

5. Time taken to travel 1 mile

 ⇒ time = distance / speed = 1 mile  / 40 miles/hr

⇒ time = 0.025 hr

8 0
3 years ago
Question: The hypotenuse of a right triangle has a length of 14 units and a side that is 9 units long. Which equation can be use
kramer

Answer:

The hypotenuse is the longest side in a triangle.

a^2=b^2+c^2.

14^2=9^2+c^2.

c^2=196-81.

c^2=115.

c=√115.

c=10.72~11cm

5 0
3 years ago
Does anyone remember how to do this???? i dont need the steps.
Paladinen [302]

Answer:

im sorry I actually forgot

Step-by-step explanation:

hope we can be friends

can i please get brainliest

4 0
3 years ago
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