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3 years ago

What is the slope of the line in the graph?

Mathematics

2 answers:

mr Goodwill [35]3 years ago

8 0

Answer:

Step-by-step explanation:

Slope is Y/x. In this case, you could do 4 /2 which would give you a slope of 2/1=2.

Sergeeva-Olga [200]3 years ago

3 0

Answer:

Step-by-step explanation:

rise 1 over run 1 1/1=1

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You get a 27% discount on a sweater that is $18 sales tax is 8.4% how much is it after text total cost

Oduvanchick [21]

Answer:

27/100×18=4.86

8.4/100×18=1.512

total is 6.372

4 0

3 years ago

Which is the best estimate for the quotient of 198.32 ÷ 9.001?

Whitepunk [10]

I would believe it to be 22

4 0

3 years ago

Read 2 more answers

After one hour, the hare had finished 2/3 of a 100-yard race. In that same time, the tortoise had finished 42 3/4 yards. How muc

andriy [413]

Answer:

23 11/12 yards or 23.9166 yards

Step-by-step explanation:

2/3 of 100 yard race is equivalent to 66 2/3 yards. Tge difference between the above and 42 3/4 yards covered by tortoise will be

66 2/3- 42 3/4= 23 11/12 yards or 23.91666 yards

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3 years ago

Mrs. Arnold is serving hamburgers to her family at six tonight for dinner she uses 1/2 pound of ground meat for each hamburger p

Alexxandr [17]

Answer:

Yes

Step-by-step explanation:

1/2 pound= 8 ounces

50/8=6.25

six burgers with some meat leftover.

8 0

2 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

5 0

3 years ago