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3 years ago

12

Travel 400 miles with 15 gallons how many with 6 gallons

2 answers:

Schach [20]3 years ago

8 0

421 because 400 plus 15 plus 6 is 421

DENIUS [597]3 years ago

7 0

1 gallons equal to 400 miles divided with 15=27
6 gallons =26.67 miles( round off equals 27) × 6= 162
Not sure about it

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Wrapping paper design with the elements numbered bisected angle

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3 years ago

Show work and steps.

nirvana33 [79]

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2 years ago

My brain is lagging:<

Lubov Fominskaja [6]

Distance between two points $(-3, 4)$ and $(5, -2)$ is $10$ units.

Mid-point of the line segment joining $(-1, -5)$ and $(7, 1)$ is $(3, -2)$ .

Degree of the given polynomial is $7$ .

6) Distance between two points $(x_1, y_1)$ and $(x_2, y_2)$ is:

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So, distance between two points $(-3, 4)$ and $(5, -2)$ is:

$=\sqrt{(5-(-3))^2+(-2-4)^2}$

$=\sqrt{(8)^2+(-6)^2}$

$=\sqrt{64+36}$

$=\sqrt{100}$

$=10$

So, option D is correct.

7) Mid-point of the line segment joining $(x_1, y_1)$ and $(x_2, y_2)$ is:

$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

Mid-point of the line segment joining $(-1, -5)$ and $(7, 1)$ is:

$(\frac{-1+7}{2}, \frac{-5+1}{2})$

$= (\frac{6}{2}, \frac{-4}{2})$

$= (3, -2)$

So, option A is correct.

8) Degree of a polynomial is the highest power of the variable in the polynomial.

$f(x)=3x^2-7x^4+9x^7+2x^3$

Here, the highest power of the variable is $7$ .

So, option B is correct.

Learn more about distance formula, mid point formula, and degree of polynomial.

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8 0

2 years ago

A= 49 sq. in.<br><br> Find the value of x. If necessary, round to the nearest tenth.

BlackZzzverrR [31]

Answer:

9.90 inches

Step-by-step explanation:

Area of a triangle is equal to base times height divided by 2.

$bh/2$

Base and height is x.

$xx/2=49$

Solve for x.

$x^2=49 \times 2$

$x^2=98$

$x=\sqrt{98}$

$x=9.899495$

8 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7Bx%7D%20%2B1%7D%7Bx-%5Csqrt%7Bx%7D%20%2B1%7D" id="TexFormula1" title="\frac

zubka84 [21]

Answer:

Step-by-step explanation:

$\frac{\sqrt{x}+1 }{x-\sqrt{x}+1 }=\frac{\sqrt{x}+1}{(x+1)-\sqrt{x}}\\\\=\frac{(\sqrt{x}+1)([x+1]+\sqrt{x})}{([x+1]-\sqrt{x})+([x+1)+\sqrt{x}])}\\\\=\frac{\sqrt{x}*x+\sqrt{x}*1+\sqrt{x}*\sqrt{x}+1*x+1*1+1*\sqrt{x}}{(x+1)^{2}-(\sqrt{x})^{2}}\\\\\\=\frac{x\sqrt{x}+\sqrt{x}+x+1+x+\sqrt{x}}{x^{2}+2x+1-x}\\\\=\frac{x\sqrt{x}+2\sqrt{x}+2x+1}{x^{2}+x+1}\\\\$

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3 years ago