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Rudik [331]
4 years ago
12

Find the jacobian of the transformation. x = u2 + uv, y = uv2

Mathematics
1 answer:
atroni [7]4 years ago
5 0
\mathbf J=\begin{bmatrix}\dfrac{\partial x}{\partial u}&\dfrac{\partial x}{\partial v}\\\\\dfrac{\partial y}{\partial u}&\dfrac{\partial y}{\partial v}\end{bmatrix}=\begin{bmatrix}2u+v&u\\v^2&2uv\end{bmatrix}

The Jacobian has determinant

\det\mathbf J=\begin{vmatrix}2u+v&u\\v^2&2uv\end{vmatrix}=(2u+v)2uv-uv^2=4u^2v+uv^2=uv(4u+v)
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Answer:

The answer in the procedure

Step-by-step explanation:

we know that

If two triangles are similar, then the ratio of its corresponding sides is equal and its corresponding interior angles are congruent

so

\frac{OK}{ON}=\frac{OJ}{OM}

substitute the values

\frac{3}{4}=\frac{30}{40}

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Therefore

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Triangles OMN and OJK are similar by AA Similarity Postulate ( The three interior angles are congruent)

Because

m<OKJ=m<ONM ----> by corresponding angles

m<KJO=m<NMO -----> by corresponding angles

m<JOK=m<MON -----> is the same angle

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3 years ago
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Answer:

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3 years ago
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Answer:

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