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Nat2105 [25]
3 years ago
14

The average of three numbers is 45. two of the numbers are equal. the last number is 89. what are the two missing numbers?

Mathematics
2 answers:
san4es73 [151]3 years ago
5 0

Answer:23

Step-by-step explanation:

Let a, b and c be the three numbers

a + b + c / 3 = 45

a = b (given)

So 2a + c / 3 = 45

c = 89 (given)

So 2a + 89 /3 = 45

     2a + 89 = 135

     2a = 46

     <em>a= 23</em>

Since  a= b<em>, b = 23</em>

<u />

So the numbers are 23 and 23

trasher [3.6K]3 years ago
4 0
The average of a set of data is equal to the sum of the values divided by the number of data present. So, if we have three numbers, the average would be:

let x, y and z represent the three numbers
average = x + y + z / 3 = 45

Two number are equal in value, so let x = y. Substituting the value to the expression of average,

45 = x + x + z / 3
45 = 2x + z / 3

It said that the last number is 89 so z is equal to 89.

45 = 2x + 89 / 3
135 = 2x + 89
46 = 2x
x = 23

Therefore, the two numbers are both 23.
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~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}

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