The initial value of 100 that doubles over each interval.
without the answer choices, I can only describe it and give you an example of the graph.
I'm assuming the function is 100*(2)^x because if it is as listed it would be a quadratic function with a vertical stretch of 100.
F = 9/5C + 32
Subtract 32 to both sides:
F - 32 = 9/5C
Divide 9/5 to both sides or multiply by its reciprocal, 5/9:
5/9(F - 32) = C
Simplify:
C = 5/9F - 160/9
Answer:
Α. 0
Step-by-step explanation:
Given A = -8 and B = 10
The distance between A and B
= B - A
= 10 - (-8)
= 10 + 8
= 18 units
4/9 of the way between A and B
= 4/9 of the distance between A and B
= 4/9 x 18 units
= 8 units.
Hence the location of the point that is 4/9 of the way from A to B
= value at point A + 8 units
= -8 + 8
= 0 (answer)
You have to isolate c
the answer is 15
Answer: 3
Step-by-step explanation:
Given
For 
to be true, the domain is given by observing the graph of two i.e. 
. In this range 
is greater than 
.
From the above domain largest integer that can satisfy the condition is 3.
