How do I go about answering questions 15?

A bag of apples weighs 7 7/8 pounds and a full bag costs $10.88. By weight 1/18 of the apples are rotten . What is the cost of t

ioda

Try Analysing The Information Like This, Step by Step;

1. We know that a full bag of 7 7/8 pounds and is $10.88.
2. Now we subtract the bad apples 7 7/8-1/18= a (now we have no bad apples).
3. Part 'a' answer will give you a no. in pounds.
4. Part 'b' - we have to find out $10.88/7 7/8 - 1/18 / 2 to give you the answer.

I hope this helps, sorry I couldn't really help you :)

7 0

3 years ago

Read 2 more answers

2. Select all transformations that must take any point A to any point B.

kherson [118]

The given transformation of reflection, rotation and translation are rigid transformation

The transformation that must take any point A to any point B are;

Rotation of 180° around the midpoint of segment AB

Reflection across the perpendicular bisector

Translation by the directed line segment AB

Reason:

Question: The given quadrilaterals ABCD and A'B'C'D' are congruent

Required; To select all transformation that must take a point A to point B

Solution:

Rotation of 180° around the midpoint of segment AB

A rotation of 180° about the midpoint of segment AB will change the places of points A and B

A(x, y) → R₁₈₀ → A'(-x, -y)

Let the coordinates of the origin be the midpoint of segment AB, and let (x, y) represent the coordinate of the point B(x, 0) we have;

∴ The coordinates of point A is A(-x, 0), which gives;

A(-x, 0) → R₁₈₀ → A'(x, 0) = point B

Therefore a rotation about the midpoint of AB must take point A to point B

Reflection across the perpendicular bisector

The reflection of a point (x, y) about y-axis gives a point (-x, y), therefore, we have;

A(-x, 0) → Reflection across the y-axis → A'(x, 0) = point B

Therefore, a reflection across the perpendicular bisector of the line AB must take the point A to point B

Translation by the directed line segment AB

A translation along the directed line segment AB of point A(-x, 0) 2·x units right gives;

A'(-x + 2·x, 0) = A'(x, 0) = Point B

Therefore, the transformations that must take any point A to any point B are;

Rotation of 180° around the midpoint of segment AB

Reflection across the perpendicular bisector

Translation by the directed line segment AB

Learn more here:

brainly.com/question/12369596

8 0

3 years ago

the name Joe is very common at a school in one out of every ten students go by the name. If there are 15 students in one class,

kumpel [21]

Using the binomial distribution, it is found that there is a 0.7941 = 79.41% probability that at least one of them is named Joe.

For each student, there are only two possible outcomes, either they are named Joe, or they are not. The probability of a student being named Joe is independent of any other student, hence, the binomial distribution is used to solve this question.

<h3>Binomial probability distribution </h3>

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

One in ten students are named Joe, hence $p = \frac{1}{10} = 0.1$ .

There are 15 students in the class, hence $n = 15$ .

The probability that at least one of them is named Joe is:

$P(X \geq 1) = 1 - P(X = 0)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{15,0}.(0.1)^{0}.(0.9)^{15} = 0.2059$

Then:

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2059 = 0.7941$

0.7941 = 79.41% probability that at least one of them is named Joe.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

8 0

2 years ago

Determine the end behavior for function f(x)=-x^4+5x^3-3

Gnesinka [82]

Answer:

Step-by-step explanation:

The dominant term of this function is x^4. The graph of x^4 starts in Quadrant II and continues in Quadrant I.

If we have y = -x^4, the graph starts in Quadrant III and continues in Quadrant IV. This is the end behavior for f(x)=-x^4+5x^3-3.

4 0

3 years ago

Cylinder has a height of 15 centimeters and a radius of 10 centimeters. What is its volume? Use ≈ 3.14 and round your answer t

tatuchka [14]

Answer: 4712.39 centimeters

Step-by-step explanation: Using the volume of a cylinder calculator, I got the answer of 4712.3889803847 centimeters, but rounded it to the nearest hundreth. Hope this helps!

3 0

3 years ago