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3 years ago

15

What is the solution set of the equation 3x^2-34x-24=0?

1 answer:

scoray [572]3 years ago

7 0

X= 6/17or the alternative form is 0.352941

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Cuál es el producto de 45.37 y 26.8

tatyana61 [14]

Answer:

uál es el pr

Step-by-step explanation:

3 0

3 years ago

Adding/subtracting polynomials <br>

Nuetrik [128]

Answer:

$g(x) - h(x) = { - x}^{4} - 11x$

Step-by-step explanation:

$g(x) = {6x}^{2} - 4x + {3x}^{4}$

$h(x) = {6x}^{2} + 4 {x}^{4} + 7x$

$g(x) - h(x)$

$({6x}^{2} - 4x + {3x}^{4}) - ( {6x}^{2} + 4 {x}^{4} + 7x)$

${6x}^{2} - 4x + {3x}^{4} - {6x}^{2} - 4 {x}^{4} - 7x$

$( {3x}^{4} - {4x}^{4}) + ( {6x}^{2} - 6x {}^{2} ) + ( - 4x - 7x)$

${ - x}^{4} - 11x$

6 0

3 years ago

Which number for (a) would result in (x-1) being a factor of p(x)=3x^3+x^2+ax-1

oee [108]

Answer:

A)3

Step-by-step explanation:

8 0

3 years ago

Triple the sum of 24 and 9

inessss [21]

so you would multiply 3 by the sum of 24 and 9...

3(24+9)=3(33)=99

4 0

4 years ago

in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference

allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

$\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}$

so that

$a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d$

$a_n=a_1+(n-1)d$

$33=8+(n-1)d$

$21=(n-1)d$

$n$ has to be an integer, which means there are 4 possible cases.

Case 1: $n-1=1$ and $d=21$ . But

$\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123$

Case 2: $n-1=21$ and $d=1$ . But

$\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123$

Case 3: $n-1=3$ and $d=7$ . But

$\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123$

Case 4: $n-1=7$ and $d=3$ . But

$\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123$

8 0

3 years ago