On a given line, (on one side) there are a total of 180°
if one line in Problem #3 is bisected by a line, with one half X and the other 120°,
do 180° (the total) minus 120° which=60°
now the hard part, that line that bisected the first line is bisecting a line that is parallel to your second line, the one with <5 and <6
this means that the big angle formed in the first one with 120° is the same angle as in the second line, leaving <5 as 120°
which means <6 is 60°, like in the top part of the problem. You're basically flipping the top line upside down, I hope it helps.
Answer:
(4,1)
Step-by-step explanation:
let J(6,6) be x1, y1
let K(2,-4) be x2, y2
midpoint = (x1+x2)/2 , (y1+y2)/2
=(6+2)/2 ,(6-4)/2
= 8/2 ,2/2
=4, 1
Answer:
Area =
square centimeter
If the circumference of the hub cap would have been smaller, then its radius would have been smaller and subsequently its area would also have been less.
Step-by-step explanation:
As we know the circumference of a circle is 
The radius of the hub cap needs to be devised to determine the area


centimeters
Area of the hub cap = 
Substituting the devised value of r in the above equation, we get -

square centimeter
If the circumference of the hub cap would have been smaller, then its radius would have been smaller and subsequently its area would also have been less.
The weight in 1980 is
kilograms
<em><u>Solution:</u></em>
From 1980 to 1990, Lior’s weight increased by 25%
His weight is "k" kilograms in 1990
<em><u>To find: weight in 1980</u></em>
This is a percentage increase problem
Let "x" be the weight in kilograms in 1980
<em><u>The percentage increase is given by formula:</u></em>

Here,
Initial value in 1980 = x
Final value in 1990 = k
Percentage increase = 25 %
<em><u>Substituting the values in formula,</u></em>

Thus the weight in kilograms in 1980 is 
Answer is Mary because
8/8 is a whole
4/8 is a half
3/8 is less than 1/2