3(-5)+4(6)<=10
(3*-5)+(4*6)<=10
(15)+(24)<=10
39<=10 N
3(2)+4(-1)<=10
(6)+(-4)<=10
2<=10 Y
3(-1)+4(4)<=10
-3+16<=10
13<=10 N
3(4)+4(0)<=10
12+0<=10 N
3(-3)+4(4)<=10
-9+16<=10
7<=10 Y
here ya go bud, im doing the same thing lol
Step-by-step explanation:
1) first eliminate constant(number without variable) you eliminate constant by doing the inverse operation(if constant is being added, then subtract)(if constant is being subtracted, then add it)
ex: if x+9=32
subtract 9 from both sides to get rid of it
x=23
2) if there is another constant but this constant is being multiplied/divided then do the opposite operation to remove it
you could multiply by 3 on both sides:
x+9=69
x=60
The last part of the question before the options is meant to be;
The hypothesis test using α = 0.1 resulted in a p-value of 0.084. Which of the following statements is true?
Answer:
B: There is a 8.3% chance that the mean number of days missed by employees at the company is below 7.
Step-by-step explanation:
Significance value is α = 0.1
p-value = 0.084
Now, we want to test the claims that the number of days missed by its employees due to illness is below the national average of 7.
Now the p-value is basically a probability.
Thus, p = 0.084 can be written as 8.4%
It seems this 8.4 is an approximate version of 8.3 because the options use 8.3%.
Thus, Option B is the closest answer.
Answer:
1414 kL
Step-by-step explanation:
The volume of the donut-shaped moat is the product of its surface area and depth. The area is the product of its centerline length and its width.
<h3>Moat area</h3>
The diameter of the centerline of the moat is (50 m -5 m) = 45 m. The length of that centerline is ...
C = πd = π(45 m) = 45π m
The area is this length times the width of the moat:
moat area = (45π m)(5 m) = 225π m²
<h3>Moat volume</h3>
The volume is the product of the area and the depth of the moat:
V = Ah = (225π m²)(2 m) = 450π m³ ≈ 1413.72 m³
1 cubic meter is 1000 liters, 1 kiloliter.
The volume of the moat is about 1414 kL.